Math Problem Statement

In einem Paketverteilerzentrum sollen 9135 Pakete innerhalb von 35 Stunden den einzelnen Zustellern zugeteilt werden. In der ersten Stunde gelingt es, lediglich 40 Pakete zuzuteilen. Um wieviel Stück muss die Anzahl der zugeteilten Pakete pro Stunde gesteigert werden, sodass nach 35 Stunden alle Pakete zugeteilt sind?

Solution

To solve this problem, we need to determine how much the number of packages distributed per hour must increase so that all 9135 packages are distributed in 35 hours. Here’s a breakdown of the solution:


Problem Summary:

  • Total packages: 91359135
  • Total hours: 3535
  • Packages distributed in the first hour: 4040
  • The number of packages distributed increases by a constant value xx every hour.
    In other words:
    • Hour 1: 4040
    • Hour 2: 40+x40 + x
    • Hour 3: 40+2x40 + 2x
    • ...
    • Hour nn: 40+(n1)x40 + (n-1)x
  • After 3535 hours, the sum of all distributed packages must equal 91359135.

We need to find the value of xx.


Mathematical Solution:

The total number of packages distributed over 3535 hours follows an arithmetic sequence where:

  • First term a=40a = 40
  • Common difference d=xd = x
  • Number of terms n=35n = 35

The sum of an arithmetic sequence is given by: Sn=n2(2a+(n1)d)S_n = \frac{n}{2} \cdot \left( 2a + (n-1)d \right)

Substitute the known values: S35=352(2(40)+(351)x)S_{35} = \frac{35}{2} \cdot \left( 2(40) + (35-1)x \right)

Set this equal to the total number of packages: 9135=352(80+34x)9135 = \frac{35}{2} \cdot \left( 80 + 34x \right)


Step-by-Step Calculation:

  1. Multiply through by 22 to eliminate the fraction: 29135=35(80+34x)2 \cdot 9135 = 35 \cdot (80 + 34x) 18270=35(80+34x)18270 = 35 \cdot (80 + 34x)

  2. Divide through by 3535: 1827035=80+34x\frac{18270}{35} = 80 + 34x 522=80+34x522 = 80 + 34x

  3. Subtract 8080 from both sides: 442=34x442 = 34x

  4. Solve for xx: x=44234x = \frac{442}{34} x=13x = 13


Final Answer:

The number of packages distributed per hour must increase by 13 packages per hour.


Verification:

  • Hour 1: 4040
  • Hour 2: 5353 (40 + 13)
  • Hour 3: 6666 (40 + 2 \cdot 13)
    ...
  • Hour 35: 40+3413=48240 + 34 \cdot 13 = 482

The total sum of packages: S35=352(2(40)+34(13))S_{35} = \frac{35}{2} \cdot \left( 2(40) + 34(13) \right) S35=352(80+442)=352522=9135S_{35} = \frac{35}{2} \cdot \left( 80 + 442 \right) = \frac{35}{2} \cdot 522 = 9135

The solution is correct.


Do you need further clarification or step-by-step details?

Related Questions:

  1. How do you derive the formula for the sum of an arithmetic sequence?
  2. What would happen if the increase xx were halved?
  3. How would the result change if the total number of hours increased to 4040?
  4. Can we solve this problem graphically to understand the distribution pattern?
  5. How do you determine the general term of an arithmetic sequence?

Tip:

When dealing with increasing or decreasing sequences, the arithmetic sequence formula is an efficient tool for summing terms systematically.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Algebra
Summation of Sequences

Formulas

Arithmetic sequence sum formula: S_n = n/2 * [2a + (n-1)d]

Theorems

Arithmetic sequence summation

Suitable Grade Level

Grades 9-10