The sequence provided in the image is:

$-101, -112, -123, -134, \ldots$

Let's determine the pattern. To do that, we subtract consecutive terms:

$-112 - (-101) = -112 + 101 = -11$ $-123 - (-112) = -123 + 112 = -11$ $-134 - (-123) = -134 + 123 = -11$

The pattern is a constant difference of $-11$ between each term. This means the sequence is an arithmetic sequence with a common difference of $-11$.

To find the next three terms: $-134 + (-11) = -145$ $-145 + (-11) = -156$ $-156 + (-11) = -167$

Thus, the next three terms are: $-145, -156, -167$

Would you like more details or further explanations?

Here are 5 related questions for further exploration:

1. How would you find the 10th term in this arithmetic sequence?
2. Can you express the general term (nth term) of this arithmetic sequence?
3. How would you sum the first 20 terms of this arithmetic sequence?
4. What happens if the common difference is positive instead of negative?
5. Can you think of a real-life situation where an arithmetic sequence with negative differences is applicable?

Tip: In arithmetic sequences, once you know the common difference and the first term, you can find any term in the sequence using the formula $a_n = a_1 + (n-1) \cdot d$.