Math Problem Statement

Effectuer les opérations suivantes : A = -6 × (-4 - 1), B = 9 × [2 - (7 - 10)], C = -4 + 20 ÷ (-2), D = -11 - (-5)

Solution

Let's solve the operations one by one from the image:

A=6×(41)A = -6 \times (-4 - 1)

  1. First, simplify the expression inside the parentheses: 41=5-4 - 1 = -5
  2. Now, multiply by 6-6: A=6×(5)=30A = -6 \times (-5) = 30

B=9×[2(710)]B = 9 \times [2 - (7 - 10)]

  1. First, simplify the expression inside the inner parentheses: 710=37 - 10 = -3
  2. Now, simplify the expression inside the square brackets: 2(3)=2+3=52 - (-3) = 2 + 3 = 5
  3. Multiply by 9: B=9×5=45B = 9 \times 5 = 45

C=4+20÷(2)C = -4 + 20 \div (-2)

  1. Perform the division first: 20÷(2)=1020 \div (-2) = -10
  2. Now, add the result to 4-4: C=4+(10)=410=14C = -4 + (-10) = -4 - 10 = -14

D=11(5)D = -11 - (-5)

  1. Simplify the double negative: 11(5)=11+5=6-11 - (-5) = -11 + 5 = -6

Summary of Results:

  • A=30A = 30
  • B=45B = 45
  • C=14C = -14
  • D=6D = -6

Would you like further details or have any questions?

Related questions:

  1. What would happen if A=6×(4+1)A = -6 \times (-4 + 1) instead of 41-4 - 1?
  2. How would the solution change for BB if the expression inside the brackets was [2+(710)][2 + (7 - 10)]?
  3. Can you solve C=4+20÷2C = -4 + 20 \div 2 instead of dividing by 2-2?
  4. What if D=11+(5)D = -11 + (-5) instead of subtracting the negative?
  5. How would changing the multiplication in AA to division affect the result?

Tip:

Always follow the order of operations: parentheses first, then exponents, followed by multiplication/division, and finally addition/subtraction (PEMDAS).

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Math Problem Analysis

Mathematical Concepts

Algebra
Arithmetic Operations
Negative Numbers
Order of Operations (PEMDAS)

Formulas

Multiplication of negative numbers
Simplification of expressions
Division of integers
Addition/Subtraction of integers

Theorems

Basic properties of addition and multiplication with negative numbers

Suitable Grade Level

Grades 5-7