Math Problem Statement

The arithmetic mean of the first n natural numbers is?

Solution

The question asks for the arithmetic mean of the first nn natural numbers. The formula for the sum of the first nn natural numbers is:

Sn=n(n+1)2S_n = \frac{n(n+1)}{2}

To find the arithmetic mean, we divide this sum by the total number of terms, which is nn. So the arithmetic mean MM is:

M=Snn=n(n+1)2n=n+12M = \frac{S_n}{n} = \frac{\frac{n(n+1)}{2}}{n} = \frac{n+1}{2}

Thus, the correct option is:

B. n+12\frac{n+1}{2}

Would you like more details on this? Here are 5 related questions:

  1. How do you derive the formula for the sum of the first nn natural numbers?
  2. What is the arithmetic mean of the first 100 natural numbers?
  3. How does the arithmetic mean of the first nn even numbers differ from this?
  4. Can this formula be used to find the mean of non-consecutive sequences?
  5. How would you generalize this for sequences other than natural numbers?

Tip: The formula for the arithmetic mean of any sequence is the sum of the terms divided by the number of terms.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Mean
Summation of Natural Numbers
Algebra

Formulas

Sum of first n natural numbers: S_n = n(n+1)/2
Arithmetic Mean: M = (n+1)/2

Theorems

Summation formula for natural numbers

Suitable Grade Level

Grades 6-8