Math Problem Statement

EVALUATE:

Solve the following problems accurately. Show your complete solution.

Solutions must be handwritten. (10 pts each)

  1. Find the area of a triangle whose sides are 16 cm, 18 cm and 28 cm.

  2. The perimeter of a rectangle is 80 cm. If the length is 14 cm. Find its width and area. How long is the diagonal?

  3. The diagonal of a square is 32 cm. Find the area, the side, and the perimeter of a square.

Solution

Sure! Here are the solutions to the problems you provided, including complete steps for each calculation.

Problem 1: Area of a Triangle

To find the area of a triangle given the sides, we can use Heron's formula.

  1. Calculate the semi-perimeter ss: s=a+b+c2=16+18+282=31 cms = \frac{a + b + c}{2} = \frac{16 + 18 + 28}{2} = 31 \text{ cm}

  2. Calculate the area AA using Heron's formula: A=s(sa)(sb)(sc)A = \sqrt{s(s-a)(s-b)(s-c)} where a=16a = 16, b=18b = 18, and c=28c = 28: A=31(3116)(3118)(3128)=31×15×13×3A = \sqrt{31(31-16)(31-18)(31-28)} = \sqrt{31 \times 15 \times 13 \times 3} A=31×15×39A = \sqrt{31 \times 15 \times 39} A=31×585140.5 cm2A = \sqrt{31 \times 585} \approx 140.5 \text{ cm}^2

Problem 2: Rectangle Perimeter, Width, Area, and Diagonal

Given the perimeter PP of the rectangle and its length ll:

  1. Use the perimeter formula: P=2(l+w)80=2(14+w)P = 2(l + w) \Rightarrow 80 = 2(14 + w) 40=14+ww=4014=26 cm40 = 14 + w \Rightarrow w = 40 - 14 = 26 \text{ cm}

  2. Calculate the area AA: A=l×w=14×26=364 cm2A = l \times w = 14 \times 26 = 364 \text{ cm}^2

  3. Calculate the diagonal dd using the Pythagorean theorem: d=l2+w2=142+262=196+676=87229.5 cmd = \sqrt{l^2 + w^2} = \sqrt{14^2 + 26^2} = \sqrt{196 + 676} = \sqrt{872} \approx 29.5 \text{ cm}

Problem 3: Square Diagonal, Area, Side, and Perimeter

Given the diagonal dd of the square:

  1. Calculate the side length ss: d=s2s=d2=322=162 cmd = s\sqrt{2} \Rightarrow s = \frac{d}{\sqrt{2}} = \frac{32}{\sqrt{2}} = 16\sqrt{2} \text{ cm}

  2. Calculate the area AA: A=s2=(162)2=256×2=512 cm2A = s^2 = (16\sqrt{2})^2 = 256 \times 2 = 512 \text{ cm}^2

  3. Calculate the perimeter PP: P=4s=4×16264290.5 cmP = 4s = 4 \times 16\sqrt{2} \approx 64\sqrt{2} \approx 90.5 \text{ cm}

Summary of Solutions

  1. Area of the triangle: approximately 140.5 cm²
  2. Width of the rectangle: 26 cm, Area: 364 cm², Diagonal: approximately 29.5 cm
  3. Area of the square: 512 cm², Side: approximately 22.63 cm, Perimeter: approximately 90.5 cm

Do you want details on any specific part or have any questions? Here are some related questions to consider:

  1. How does Heron's formula work for triangles with different side lengths?
  2. What is the relationship between the diagonal and the sides of a rectangle?
  3. How does the area of a square change if the diagonal is doubled?
  4. What other methods can be used to calculate the area of a triangle?
  5. Can you explain the Pythagorean theorem in more detail?

Tip: Always double-check your calculations for accuracy, especially in geometric problems!

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Math Problem Analysis

Mathematical Concepts

Geometry
Trigonometry
Algebra

Formulas

Heron's formula for area of triangle: A = √(s(s-a)(s-b)(s-c))
Perimeter of rectangle: P = 2(l + w)
Area of rectangle: A = l × w
Diagonal of rectangle: d = √(l² + w²)
Diagonal of square: d = s√2
Area of square: A = s²
Perimeter of square: P = 4s

Theorems

Heron's formula
Pythagorean theorem

Suitable Grade Level

Grades 7-10