Math Problem Statement

In the figure, B is a point lying on AC such that AB : BC = 1 : 2. E is a point on AF such that AE : EF = 3 : 1. It is given that AF || BD and CF || DE. If the area of the trapezium ABDE is 7 cm², then the area of ΔACF is?

Solution

Problem Breakdown:

We need to calculate the area of ACF\triangle ACF based on the given figure and information:

Key Information:

  1. BB lies on ACAC, and AB:BC=1:2AB : BC = 1 : 2.
  2. EE is a point on AFAF, and AE:EF=3:1AE : EF = 3 : 1.
  3. AFBDAF \parallel BD and CFDECF \parallel DE, meaning ABDEABDE is a trapezium.
  4. Area of trapezium ABDE=7cm2ABDE = 7 \, \text{cm}^2.

We are tasked to find the area of ACF\triangle ACF.


Solution Approach:

1. Ratios along ACAC:

From AB:BC=1:2AB : BC = 1 : 2, the total length ACAC can be divided into three equal parts:

  • AB=13ACAB = \frac{1}{3} AC,
  • BC=23ACBC = \frac{2}{3} AC.

2. Ratios along AFAF:

From AE:EF=3:1AE : EF = 3 : 1, the total length AFAF can be divided into four equal parts:

  • AE=34AFAE = \frac{3}{4} AF,
  • EF=14AFEF = \frac{1}{4} AF.

3. Trapezium area formula:

The area of a trapezium is given by: Area=12(Sum of parallel sides)×Height.\text{Area} = \frac{1}{2} (\text{Sum of parallel sides}) \times \text{Height}.

Here:

  • Parallel sides are ABAB and DEDE,
  • The height is along AFAF, proportional to the distances divided by AE:EFAE : EF.

Using the ratio properties and parallel lines, we relate the sub-triangles’ and trapezium’s areas proportionally to ACF\triangle ACF.

4. Area proportions:

Using similarity of triangles and area ratios: Area of ACFACAF.\text{Area of } \triangle ACF \propto AC \cdot AF. We will compute this step-by-step.


Let me perform the detailed calculations. Define the known data area_trapezium_ABDE = 7 # Area of trapezium ABDE in cm^2

Ratios

AB_ratio = 1 / 3 # AB:AC BC_ratio = 2 / 3 # BC:AC AE_ratio = 3 / 4 # AE:AF EF_ratio = 1 / 4 # EF:AF

Calculate the ratio of the areas using similarity and proportionality rules

ABDE and ACF relationship:

Trapezium height depends on AE:EF and sub-area proportions

Total ratio of similarity (length proportions multiply area proportion)

triangle_area_ratio_ACF_to_ABDE = (1 / AB_ratio) * (1 / AE_ratio) # Proportional similarity

Area of ACF

area_triangle_ACF = triangle_area_ratio_ACF_to_ABDE * area_trapezium_ABDE area_triangle_ACFThe area of ACF\triangle ACF is 28cm228 \, \text{cm}^2.


Explanation:

Using proportionality and the given ratios:

  1. The area of ACF\triangle ACF is determined by the relationship between the triangle's dimensions and the trapezium ABDEABDE, taking into account the parallelism and the ratios AB:BCAB : BC and AE:EFAE : EF.
  2. The area scaling factor between ABDEABDE and ACF\triangle ACF is proportional to the product of length ratios along ACAC and AFAF.

Would you like a detailed step-by-step breakdown of the calculations?


5 Related Questions:

  1. How do proportionality rules in similar triangles affect area calculations?
  2. Why does the parallelism of AFBDAF \parallel BD and CFDECF \parallel DE ensure trapezium ABDEABDE?
  3. How can we verify the scaling factor between the triangle and trapezium?
  4. What are the implications of dividing ACAC and AFAF into ratios for other segments?
  5. How would the problem change if one ratio (e.g., AB:BCAB : BC) was different?

Tip:

Always check for parallel lines and proportionality relationships in geometric problems; they often simplify area and ratio calculations significantly!

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Math Problem Analysis

Mathematical Concepts

Geometry
Ratios and Proportions
Areas of Triangles and Trapeziums

Formulas

Area of trapezium = (1/2) * (sum of parallel sides) * height
Area scaling factor = (similarity ratio)^2

Theorems

Basic Proportionality Theorem (Thales' theorem)
Area Ratio Theorem in Similar Triangles

Suitable Grade Level

Grades 10-12