Math Problem Statement

The area of a regular hexagon circumscribed around a circle is 36√3 cm². Find the area of a regular quadrilateral inscribed in this circle.

Solution

To solve this, let's break down the problem step by step.

Step 1: Relationship between the hexagon and the circle

The given regular hexagon is circumscribed around a circle, which means that the circle is inscribed in the hexagon. For a regular hexagon:

  • The radius rr of the circle is equal to the apothem of the hexagon, which is also the distance from the center of the hexagon to the midpoint of its sides.

The area AA of a regular hexagon is given by:

A=332s2A = \frac{3\sqrt{3}}{2} s^2

where ss is the side length of the hexagon.

Step 2: Use the area to find the side length of the hexagon

The problem states that the area of the hexagon is 36336\sqrt{3} cm². So, set the formula for the area equal to this value:

332s2=363\frac{3\sqrt{3}}{2} s^2 = 36\sqrt{3}

Simplify and solve for s2s^2:

32s2=36\frac{3}{2} s^2 = 36

Multiply both sides by 2 to eliminate the fraction:

3s2=723s^2 = 72

Now divide by 3:

s2=24s^2 = 24

Taking the square root of both sides:

s=24=26s = \sqrt{24} = 2\sqrt{6}

Step 3: Calculate the radius of the circle

For a regular hexagon, the radius rr of the circumscribed circle is equal to the side length ss of the hexagon. Therefore:

r=26r = 2\sqrt{6}

Step 4: Area of the inscribed square (regular quadrilateral)

Now, we need to find the area of a square inscribed in the same circle. The diagonal of the square is equal to the diameter of the circle, which is 2r2r.

Thus, the diagonal dd of the square is:

d=2r=2×26=46d = 2r = 2 \times 2\sqrt{6} = 4\sqrt{6}

The relationship between the side length aa of a square and its diagonal dd is:

d=a2d = a\sqrt{2}

Substituting d=46d = 4\sqrt{6}:

46=a24\sqrt{6} = a\sqrt{2}

Solving for aa:

a=462=43a = \frac{4\sqrt{6}}{\sqrt{2}} = 4\sqrt{3}

Step 5: Calculate the area of the square

The area AsquareA_{\text{square}} of the square is:

Asquare=a2=(43)2=16×3=48 cm2A_{\text{square}} = a^2 = (4\sqrt{3})^2 = 16 \times 3 = 48 \text{ cm}^2

Thus, the area of the square inscribed in the circle is 48 cm².


Would you like more details on any part of the solution, or do you have further questions?

Here are some related questions:

  1. How do you calculate the area of other polygons inscribed in a circle?
  2. What is the relationship between the radius of a circle and different polygons inscribed within it?
  3. Can the same approach be applied to non-regular polygons?
  4. What is the area of a triangle inscribed in the same circle?
  5. How does the side length of a square change if the circle's radius doubles?

Tip: When working with inscribed and circumscribed polygons, it's important to understand the relationship between side lengths, radii, and areas for regular shapes.

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Math Problem Analysis

Mathematical Concepts

Geometry
Regular Polygons
Inscribed and Circumscribed Shapes
Area Calculation

Formulas

Area of a regular hexagon: A = (3√3/2) s²
Relationship between side length of hexagon and radius: r = s
Diagonal of a square inscribed in a circle: d = 2r
Area of a square: A = a², where a = d/√2

Theorems

Properties of Regular Polygons
Pythagorean Theorem
Relationship between Circumscribed and Inscribed Polygons

Suitable Grade Level

Grades 9-11