Using the previous information (To find the coordinates of the points where the two curves intersect, we need to set the two equations equal to each other since they intersect at those points. Given: (y = 2x² - 8x + 5 ) ---(1) (y = x² - 4x + 2) ---(2) Setting equation (1) equal to equation (2) gives: (2x² - 8x + 5 = x² - 4x + 2) Now, we need to solve this quadratic equation to find the x-values of the points of intersection. Subtracting (x² - 4x + 2) from both sides, we get: (2x² - x² - 8x + 4x + 5 - 2 = 0) (x² - 4x + 3 = 0) To solve this quadratic equation, we can either factorize it or use the quadratic formula. Factoring is easier in this case: ((x - 3)(x - 1) = 0) This gives us x = 3 or x = 1 as the x-coordinates of the points of intersection. To find the y-coordinates, we substitute these x-values back into either of the original equations. Let's use equation (2): For x = 3: (y = (3)² - 4(3) + 2) (y = 9 - 12 + 2) (y = -1) So, one point of intersection is (3, -1). For x = 1: (y = (1)² - 4(1) + 2) (y = 1 - 4 + 2) (y = -1) The other point of intersection is (1, -1) ) answer the following : If O is the origin, find the area of of the triangle OAB.