The image shows a triangle where the base and height are expressed as algebraic expressions: the base is $2x - 8$ and the height is $2x - 5$. To find the area of the triangle, we can use the formula for the area of a triangle:

$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$

Substituting the given expressions for the base and height:

$\text{Area} = \frac{1}{2} \times (2x - 8) \times (2x - 5)$

Now, we need to simplify this expression. Let's expand the terms:

$(2x - 8)(2x - 5) = 4x^2 - 10x - 16x + 40 = 4x^2 - 26x + 40$

So, the area becomes:

$\text{Area} = \frac{1}{2} \times (4x^2 - 26x + 40)$

Now, distribute the $\frac{1}{2}$:

$\text{Area} = 2x^2 - 13x + 20$

Thus, the area of the triangle is:

$\boxed{2x^2 - 13x + 20}$

Let me know if you'd like further clarification or have any other questions! Here are some related questions:

1. How do you factor a quadratic expression like $2x^2 - 13x + 20$?
2. What happens if we substitute a value for $x$ into the area expression?
3. Can we use the same formula for the area of a triangle when the triangle is not a right triangle?
4. How do you solve for $x$ if you're given the area of the triangle?
5. What is the geometric interpretation of multiplying the base and height of a triangle?

Tip: When simplifying algebraic expressions like this one, always distribute carefully and combine like terms to make the problem easier!