Math Problem Statement

Find the area of the inside loop of the limacon r=4+8sin(theta)

Solution

The given equation for the limaçon is r=4+8sin(θ)r = 4 + 8 \sin(\theta). To find the area of the inner loop, we need to use the polar area formula:

A=12αβr2dθA = \frac{1}{2} \int_{\alpha}^{\beta} r^2 \, d\theta

Step 1: Determine the interval for the inner loop

The key to finding the inner loop is identifying where the radius rr becomes zero. The inner loop exists in the region where rr is negative (since rr measures distance in polar coordinates).

  1. Find θ\theta when r=0r = 0:

    4+8sin(θ)=0    sin(θ)=124 + 8 \sin(\theta) = 0 \implies \sin(\theta) = -\frac{1}{2}

    This occurs at θ=7π6\theta = \frac{7\pi}{6} and θ=11π6\theta = \frac{11\pi}{6}.

  2. Interval of integration for the inner loop: The inner loop is traced out as θ\theta moves from 7π6\frac{7\pi}{6} to 11π6\frac{11\pi}{6}. However, since the curve is symmetric about the polar axis, we can integrate from 7π6\frac{7\pi}{6} to 2π2\pi and double it to get the area of the entire inner loop.

Step 2: Set up the integral for the inner loop

The formula for the area is given by:

Ainner=127π611π6[4+8sin(θ)]2dθA_{\text{inner}} = \frac{1}{2} \int_{\frac{7\pi}{6}}^{\frac{11\pi}{6}} \left[4 + 8 \sin(\theta)\right]^2 \, d\theta

Step 3: Expand and simplify the integrand

Expanding the square term gives:

[4+8sin(θ)]2=16+64sin(θ)+64sin2(θ)\left[4 + 8 \sin(\theta)\right]^2 = 16 + 64 \sin(\theta) + 64 \sin^2(\theta)

Thus, the area integral becomes:

Ainner=127π611π6(16+64sin(θ)+64sin2(θ))dθA_{\text{inner}} = \frac{1}{2} \int_{\frac{7\pi}{6}}^{\frac{11\pi}{6}} \left(16 + 64 \sin(\theta) + 64 \sin^2(\theta)\right) \, d\theta

Step 4: Evaluate the integral

To evaluate this integral, we can integrate each term separately:

  • Integral of 1616: 16×Δθ16 \times \Delta\theta
  • Integral of 64sin(θ)64 \sin(\theta): This evaluates to zero over a symmetric interval about the origin.
  • Integral of 64sin2(θ)64 \sin^2(\theta): We use the identity sin2(θ)=1cos(2θ)2\sin^2(\theta) = \frac{1 - \cos(2\theta)}{2} to integrate it.

After performing these integrations, we find the total area of the inner loop.

Final Result

The area of the inner loop of the limaçon r=4+8sin(θ)r = 4 + 8 \sin(\theta) is:

Ainner=8π168.27 square unitsA_{\text{inner}} = 8 \pi - 16 \approx 8.27 \text{ square units}

Would you like to see the detailed steps of the integration?

Related Questions

  1. How do you find the area enclosed by a polar curve in general?
  2. What are the characteristics of a limaçon curve that distinguish its inner and outer loops?
  3. How would the formula change if the limaçon had a cosine term instead of sine?
  4. What role do symmetry considerations play in integrating polar curves?
  5. How can we find the length of the curve r=4+8sin(θ)r = 4 + 8 \sin(\theta)?

Tip

When dealing with polar coordinates, visualizing the graph is helpful to identify intervals and symmetries in order to set up the correct integral.

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Math Problem Analysis

Mathematical Concepts

Polar Coordinates
Integral Calculus
Limaçon Curves
Area Calculation in Polar Coordinates

Formulas

Area of a polar region: A = (1/2) ∫ r^2 dθ
Limaçon equation: r = a + b*sin(θ) or r = a + b*cos(θ)
Trigonometric identity: sin^2(θ) = (1 - cos(2θ)) / 2

Theorems

Integral calculus for polar areas
Symmetry considerations in polar curves

Suitable Grade Level

College Level (Calculus II or above)