The shape in the image consists of a rectangle and a right triangle placed side by side. To find the area of the entire figure, we can compute the area of the rectangle and the area of the triangle separately and then add them together.

1. Area of the rectangle: The rectangle has dimensions of 8 cm (height) and 8 cm (width). $A_{\text{rectangle}} = \text{height} \times \text{width} = 8 \, \text{cm} \times 8 \, \text{cm} = 64 \, \text{cm}^2$

2. Area of the triangle: The triangle has a base of 6 cm and a height of 8 cm (the same as the height of the rectangle, since the triangle is attached to it along that height). $A_{\text{triangle}} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 6 \, \text{cm} \times 8 \, \text{cm} = 24 \, \text{cm}^2$

3. Total area of the figure: The total area is the sum of the areas of the rectangle and the triangle. $A_{\text{total}} = A_{\text{rectangle}} + A_{\text{triangle}} = 64 \, \text{cm}^2 + 24 \, \text{cm}^2 = 88 \, \text{cm}^2$

Thus, the total area of the figure is 88 cm².

Would you like further details or have any questions?

Here are 5 related questions:

1. How do you find the area of different geometric shapes like parallelograms or trapezoids?
2. What would happen if the dimensions of the triangle were doubled?
3. How can you find the perimeter of this figure?
4. What if the triangle and rectangle were rotated or combined in a different way—how would that affect the area?
5. How would you calculate the area if this figure were part of a 3D shape (like a prism)?

Tip: When dealing with composite figures, breaking them down into simpler shapes like triangles and rectangles makes calculations easier!