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To find the arc length of a parametric curve \( \mathbf{r}(t) = \langle 10\sqrt{2}t, e^{10t}, e^{-10t} \rangle \) for \( 0 \leq t \leq 1 \), we use the formula for the arc length of a vector function \( \mathbf{r}(t) \) over the interval \( [a, b] \):

\[
L = \int_a^b \|\mathbf{r}'(t)\| \, dt
\]

### Step 1: Compute \( \mathbf{r}'(t) \)
First, differentiate each component of \( \mathbf{r}(t) \) with respect to \( t \).

- \( \frac{d}{dt}(10\sqrt{2}t) = 10\sqrt{2} \)
- \( \frac{d}{dt}(e^{10t}) = 10e^{10t} \)
- \( \frac{d}{dt}(e^{-10t}) = -10e^{-10t} \)

Thus, \( \mathbf{r}'(t) = \langle 10\sqrt{2}, 10e^{10t}, -10e^{-10t} \rangle \).

### Step 2: Compute \( \|\mathbf{r}'(t)\| \)
Now, find the magnitude of \( \mathbf{r}'(t) \):

\[
\|\mathbf{r}'(t)\| = \sqrt{(10\sqrt{2})^2 + (10e^{10t})^2 + (-10e^{-10t})^2}
\]

Simplify each term:

\[
= \sqrt{(100 \times 2) + (100e^{20t}) + (100e^{-20t})}
\]
\[
= \sqrt{200 + 100e^{20t} + 100e^{-20t}}
\]

Notice that \( e^{20t} + e^{-20t} \) can be expressed using the identity:

\[
e^{20t} + e^{-20t} = 2\cosh(20t)
\]

Thus, we have:

\[
\|\mathbf{r}'(t)\| = \sqrt{200 + 100 \times 2\cosh(20t)} = \sqrt{200 + 200\cosh(20t)}
\]

\[
\|\mathbf{r}'(t)\| = \sqrt{200(1 + \cosh(20t))}
\]

### Step 3: Compute the Arc Length Integral
Now, compute the arc length by integrating \( \|\mathbf{r}'(t)\| \) from \( t = 0 \) to \( t = 1 \):

\[
L = \int_0^1 \sqrt{200(1 + \cosh(20t))} \, dt
\]

Factor out \( \sqrt{200} \):

\[
L = \sqrt{200} \int_0^1 \sqrt{1 + \cosh(20t)} \, dt
\]

This integral does not have a simple elementary form, so it would typically be evaluated using numerical methods. However, we can leave it in this form for now, or approximate it using tools like numerical integration.

Would you like more details on how to compute the integral numerically or further clarification?

### 5 Related Questions:
1. What is the physical meaning of the arc length in a parametric curve?
2. How is the hyperbolic cosine function \( \cosh(x) \) related to exponential functions?
3. What are other methods for calculating arc length if the integral is difficult to solve analytically?
4. How does arc length change if we scale the curve in one or more directions?
5. What is the difference between arc length in 2D and 3D parametric curves?

**Tip:** When solving integrals that involve hyperbolic functions or exponentials, checking for simplification using identities like \( \cosh(x) \) can make computations easier.

Find the arc length of the curve r(t) = ⟨10√2t, e^(10t), e^(-10t)⟩, 0 ≤ t ≤ 1.

Learn how to calculate the arc length of the parametric curve r(t) = ⟨10√2t, e^(10t), e^(-10t)⟩ for 0 ≤ t ≤ 1 using calculus. The solution includes differentiating vector functions and simplifying using hyperbolic identities.

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