Math Problem Statement

A surveyor, standing 10 ft from the base of a building, measures the angle of elevation to the top of the building to be 5 degrees. How accurately must the angle be measured for the percentage error in estimating the height of the building to be less than 3 percent?

Solution

This problem is asking us to determine how accurately the angle of elevation must be measured to ensure that the percentage error in estimating the height of the building remains below 3%. Let’s break it down step by step.

Given:

  • Distance from the base of the building = 10ft10 \, \text{ft}
  • Measured angle of elevation = 55^\circ
  • Acceptable percentage error = 3%3\%

Key relationships:

  1. Height of the building (hh): Using trigonometry: h=10tan(θ)h = 10 \cdot \tan(\theta) where θ\theta is the angle of elevation.

  2. Error propagation: The error in the height due to an error in the angle is calculated using the derivative of hh with respect to θ\theta: dhh=sec2(θ)dθ\frac{dh}{h} = \sec^2(\theta) \cdot d\theta Percentage error in hh: Percentage error=(sec2(θ)dθ)100\text{Percentage error} = \left( \sec^2(\theta) \cdot d\theta \right) \cdot 100

  3. Condition: To keep the error below 3%3\%, we set: sec2(θ)dθ100<3\sec^2(\theta) \cdot d\theta \cdot 100 < 3 Simplify: dθ<3100sec2(θ)d\theta < \frac{3}{100 \cdot \sec^2(\theta)}

Step-by-step Calculation:

  1. Compute sec2(5)\sec^2(5^\circ): sec2(5)=1+tan2(5)\sec^2(5^\circ) = 1 + \tan^2(5^\circ) Using tan(5)0.08749\tan(5^\circ) \approx 0.08749: sec2(5)=1+(0.08749)21.00765\sec^2(5^\circ) = 1 + (0.08749)^2 \approx 1.00765

  2. Plug sec2(5)\sec^2(5^\circ) into the inequality: dθ<31001.007653100.7650.02976radiansd\theta < \frac{3}{100 \cdot 1.00765} \approx \frac{3}{100.765} \approx 0.02976 \, \text{radians}

  3. Convert dθd\theta to degrees: dθ(degrees)=0.02976180π1.705d\theta \, (\text{degrees}) = 0.02976 \cdot \frac{180}{\pi} \approx 1.705^\circ

Final Answer:

The angle of elevation must be measured with an accuracy of approximately ±1.7\pm 1.7^\circ to ensure the percentage error in estimating the height is less than 3%.


Would you like a more detailed explanation of any step or further assistance? Here are five related questions to explore:

  1. How would the required accuracy change if the angle of elevation were larger, say 1010^\circ?
  2. What happens to the error if the distance from the building increases?
  3. How is the calculation affected if the percentage error tolerance is tightened to 1%?
  4. Can this formula be generalized to any angle and distance?
  5. How would rounding errors affect the measurement and error calculation?

Tip: Always ensure that trigonometric calculations are done with appropriate units (radians vs degrees).

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Error Propagation
Percentage Error

Formulas

Height of the building: h = 10 * tan(θ)
Percentage error: sec²(θ) * dθ * 100
Error condition: dθ < 3 / (100 * sec²(θ))

Theorems

Trigonometric relationship for tangent
Derivative of tangent function: d(tan(θ))/dθ = sec²(θ)

Suitable Grade Level

Grades 11-12