Math Problem Statement

Найти угол между прямыми: l1: 5x - y - 6 = 0 и l2: y + (1/5)x - (17/5) = 0

Solution

The problem asks to find the angle between two lines given their equations:

  1. l1:5xy6=0l_1: 5x - y - 6 = 0
  2. l2:y+15x175=0l_2: y + \frac{1}{5}x - \frac{17}{5} = 0

Solution:

Step 1: Rewrite the equations in slope-intercept form (y=mx+by = mx + b):

  1. For l1:5xy6=0l_1: 5x - y - 6 = 0:
    Rearrange to solve for yy:
    y=5x6y = 5x - 6
    Here, the slope (m1m_1) is 55.

  2. For l2:y+15x175=0l_2: y + \frac{1}{5}x - \frac{17}{5} = 0:
    Rearrange to solve for yy:
    y=15x+175y = -\frac{1}{5}x + \frac{17}{5}
    Here, the slope (m2m_2) is 15-\frac{1}{5}.

Step 2: Use the formula for the angle between two lines:

The angle θ\theta between two lines with slopes m1m_1 and m2m_2 is given by:
tanθ=m1m21+m1m2\tan\theta = \left| \frac{m_1 - m_2}{1 + m_1m_2} \right|

Substitute m1=5m_1 = 5 and m2=15m_2 = -\frac{1}{5}:
tanθ=5(15)1+5(15)\tan\theta = \left| \frac{5 - \left(-\frac{1}{5}\right)}{1 + 5\left(-\frac{1}{5}\right)} \right|

Simplify: tanθ=5+1511\tan\theta = \left| \frac{5 + \frac{1}{5}}{1 - 1} \right|

The denominator becomes 00, indicating that the lines are perpendicular. Thus, the angle θ=90\theta = 90^\circ.

Final Answer:

The angle between the lines is 9090^\circ.

Would you like a detailed derivation or have any questions?


Related Questions:

  1. How do you find the slopes of lines from their equations?
  2. What is the geometric meaning of perpendicular lines?
  3. Can you calculate the angle between lines if their slopes are undefined?
  4. What does it mean if the denominator in tanθ\tan\theta is zero?
  5. How does the formula for tanθ\tan\theta change if one line is vertical?

Tip:

Always verify the slopes carefully, as small errors can lead to incorrect conclusions about angles.

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Math Problem Analysis

Mathematical Concepts

Geometry
Coordinate Geometry
Slope of a Line
Angle Between Lines

Formulas

Slope-intercept form: y = mx + b
Angle between lines: tan(θ) = |(m1 - m2) / (1 + m1 * m2)|

Theorems

Perpendicularity Criterion in Coordinate Geometry

Suitable Grade Level

Grades 10-12