Math Problem Statement

Use the graph of f to determine each of the following. ​(a) the domain of f ​(b) the range of f ​(c) the zeros of f ​(d) f left parenthesis 0 right parenthesisf(0) ​(e) the intervals on which f is increasing ​(f) the intervals on which f is decreasing ​(g) the values for which ​f(x)less than or equals≤0 ​(h) any relative maxima or minima ​(i) the​ value(s) of x for which f left parenthesis x right parenthesis equals 4f(x)=4 ​(j) Is f left parenthesis negative 2 right parenthesisf(−2) positive or​ negative?

Use the graph of f to determine each of the following. (a) the domain of f (b) the range of f (c) the zeros of f (d) f(0) (e) the intervals on which f is increasing (f) the intervals on which f is decreasing (g) the values for which f(x) ≤ 0 (h) any relative maxima or minima (i) the values of x for which f(x) = 4 (j) Is f(-2) positive or negative?

Solution

Let's analyze the graph provided step by step to answer each of the questions about the function f(x)f(x).

(a) Domain of ff

The domain is the set of all possible input values (x-values) for which the function is defined. From the graph, the function starts at x=8x = -8 and continues to x=4x = 4. Therefore, the domain is: Domain: [8,4]\text{Domain: } [-8, 4]

(b) Range of ff

The range is the set of all possible output values (y-values). From the graph, the function has a maximum value of y=4y = 4 and goes down to y=5y = -5. Therefore, the range is: Range: [5,4]\text{Range: } [-5, 4]

(c) Zeros of ff

Zeros are the x-values where f(x)=0f(x) = 0 (i.e., where the graph crosses the x-axis). From the graph, the zeros occur at x=6x = -6 and x=2x = 2. Zeros: x=6,2\text{Zeros: } x = -6, 2

(d) f(0)f(0)

To find f(0)f(0), locate where x=0x = 0 on the graph and find the corresponding yy-value. From the graph: f(0)=2f(0) = 2

(e) Intervals where ff is increasing

The function is increasing where the graph is going upward. This occurs from x=8x = -8 to x=4x = -4 (since the graph rises from left to right in this interval). Increasing on: [8,4]\text{Increasing on: } [-8, -4]

(f) Intervals where ff is decreasing

The function is decreasing where the graph is going downward. This occurs from x=4x = -4 to x=4x = 4. Decreasing on: [4,4]\text{Decreasing on: } [-4, 4]

(g) Values where f(x)0f(x) \leq 0

The values of xx where the graph is below or on the x-axis (i.e., f(x)0f(x) \leq 0) are from x=8x = -8 to x=6x = -6, and from x=2x = 2 to x=4x = 4. [ f(x) \leq 0 \text{ for } x \in [-8, -6] \cup [2, 4] ]

(h) Relative maxima or minima

  • Relative maximum: The highest point within a certain interval. The relative maximum occurs at x=4x = -4, where f(x)=4f(x) = 4.
  • Relative minimum: There is no relative minimum, as the function does not have any lower turning points before continuing downward.

(i) Values of xx for which f(x)=4f(x) = 4

The value of f(x)=4f(x) = 4 occurs at x=4x = -4. f(x)=4 at x=4f(x) = 4 \text{ at } x = -4

(j) Is f(2)f(-2) positive or negative?

To find f(2)f(-2), locate x=2x = -2 on the graph and find the corresponding yy-value. From the graph, f(2)f(-2) is positive because the graph is above the x-axis at x=2x = -2. f(2) is positive.f(-2) \text{ is positive.}


Would you like further details or explanations? Here are some related questions to consider:

  1. How do you determine the relative maxima and minima of a function from its graph?
  2. What is the difference between absolute maxima/minima and relative maxima/minima?
  3. How can the intervals of increase and decrease be found using the derivative of a function?
  4. How would you describe the behavior of the function at x=4x = 4 where the function terminates?
  5. Can a function have more than one relative maximum?

Tip: A function's domain refers to the x-values for which the function is defined, and the range refers to the y-values the function can take. Understanding this distinction is key when interpreting graphs.

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Math Problem Analysis

Mathematical Concepts

Graph Interpretation
Function Analysis
Quadratics

Formulas

N/A (graphical interpretation)

Theorems

N/A (based on the graph)

Suitable Grade Level

Grades 9-12