Math Problem Statement

f(a)=6a^2+3a-5

Solution

The function f(a)=6a2+3a5f(a) = 6a^2 + 3a - 5 is a quadratic function, as the highest degree of the variable aa is 2.

Would you like me to analyze the function further by calculating its properties (e.g., vertex, roots, derivative, etc.) or solve any specific problem involving this function?

Here are 5 related questions:

  1. What are the roots (solutions) of the quadratic equation 6a2+3a5=06a^2 + 3a - 5 = 0?
  2. How do you find the vertex of the parabola described by this function?
  3. What is the derivative of f(a)f(a) with respect to aa?
  4. What are the y-intercepts and x-intercepts of the function?
  5. How can you graph the function f(a)=6a2+3a5f(a) = 6a^2 + 3a - 5?

Tip: When solving a quadratic equation, the discriminant b24acb^2 - 4ac can tell you if the roots are real or complex.

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Vertex of a Parabola
Derivative of a Quadratic Function
Graphing Quadratic Functions
Quadratic Equations

Formulas

Quadratic equation formula: ax^2 + bx + c = 0

Theorems

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Suitable Grade Level

High School