Math Problem Statement
Solution
Let's analyze the graph to answer each part of the question:
Observations:
This is a parabolic graph that opens downwards, suggesting that it represents a quadratic function with a negative leading coefficient.
Answers:
-
Sign of the Leading Coefficient (a):
Since the parabola opens downward, the leading coefficient is negative. -
Vertex (b):
The highest point on this graph (the vertex) is at (-2, 4). -
Axis of Symmetry (c):
The axis of symmetry for a parabola is a vertical line passing through the x-coordinate of the vertex. Here, it’s at x = -2. -
Intervals of Increase and Decrease (d):
- Increasing interval: From (-∞, -2), as the function values increase as x moves towards -2.
- Decreasing interval: From (-2, ∞), as the function values decrease as x moves away from -2.
-
Domain and Range (e):
- Domain: All real numbers, so (-∞, ∞).
- Range: Since the vertex is the maximum point at y = 4, the range is (-∞, 4].
Would you like a further explanation for any part?
Here are some additional related questions for practice:
- What would be the effect on the graph if the leading coefficient were positive?
- How would the axis of symmetry change if the vertex shifted?
- Can you find the equation of this parabola based on the given vertex and symmetry?
- What are the x-intercepts of this parabola, if any?
- How would the intervals of increase and decrease change if the vertex were at a lower y-value?
Tip: The vertex form of a parabola is helpful in identifying the vertex and axis of symmetry quickly.
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Math Problem Analysis
Mathematical Concepts
Algebra
Quadratic Functions
Graphing Parabolas
Formulas
Vertex form of a parabola y = a(x - h)^2 + k
Theorems
Properties of Parabolas
Symmetry in Quadratic Functions
Suitable Grade Level
Grades 9-10
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