Math Problem Statement
If x<l, then f'(*) = 6()>0 so f; If1<x< 2, then f(x) = 6(+) (<0 and sof: If x> 2, then f' (x) = 6(+) (+) > 0 andso ↑. , Thusf is increasing on (-, 1) and (2, 0) and is decreasing on (1 Scanned
Solution
It looks like the text you've provided is a bit scrambled, but I can help clarify the mathematical reasoning for determining the behavior of a function based on the sign of its derivative .
Here is a clearer interpretation of the provided information:
-
When :
This indicates that the derivative of is positive when is less than 1. Therefore, the function is increasing on the interval . -
When :
This shows that the derivative is negative for in the interval . Consequently, the function is decreasing on this interval. -
When :
The derivative becomes positive again for , meaning that is increasing on the interval .
Summary:
- is increasing on the intervals and .
- is decreasing on the interval .
Would you like me to go into further details or explain anything else?
Here are five related questions that might interest you:
- How do you determine the critical points of a function using its derivative?
- What is the significance of the second derivative in analyzing the behavior of a function?
- How do inflection points relate to the concavity of a function?
- Can you explain how to sketch a graph of a function based on its first and second derivatives?
- What are some common applications of increasing and decreasing functions in real-life scenarios?
Tip: Understanding the signs of the first derivative helps you determine where a function is increasing or decreasing, which is crucial for sketching its graph and understanding its behavior.
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Math Problem Analysis
Mathematical Concepts
Calculus
Derivatives
Function Behavior
Formulas
f'(x) > 0 (function increasing)
f'(x) < 0 (function decreasing)
Theorems
First Derivative Test
Suitable Grade Level
Grades 11-12
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