Math Problem Statement

The function f(x) = |x| + x ^ 2 + x ^ 4 will be?

Solution

To analyze the function f(x)=x+x2+x4f(x) = |x| + x^2 + x^4, let's consider its behavior across different domains of xx.

1. Analyzing the Function on Different Domains

The absolute value function x|x| affects the behavior of f(x)f(x) depending on whether xx is non-negative or negative:

  • For x0x \geq 0: x=x|x| = x Thus, the function simplifies to: f(x)=x+x2+x4f(x) = x + x^2 + x^4

  • For x<0x < 0: x=x|x| = -x Hence, the function becomes: f(x)=x+x2+x4f(x) = -x + x^2 + x^4

2. Behavior of f(x)f(x) Based on the Sign of xx

Case 1: x0x \geq 0

When x0x \geq 0, the function is: f(x)=x+x2+x4f(x) = x + x^2 + x^4 All the terms x,x2,x4x, x^2, x^4 are non-negative for x0x \geq 0, so f(x)0f(x) \geq 0. This function is continuous and differentiable for all x0x \geq 0.

Case 2: x<0x < 0

When x<0x < 0, the function is: f(x)=x+x2+x4f(x) = -x + x^2 + x^4 Since x<0x < 0, x>0-x > 0. The terms x2x^2 and x4x^4 are also positive, meaning that f(x)>0f(x) > 0 for x<0x < 0 as well. Thus, f(x)f(x) remains continuous and differentiable for all xx.

3. Key Characteristics of the Function f(x)=x+x2+x4f(x) = |x| + x^2 + x^4

  • Continuity: The function f(x)f(x) is continuous everywhere because x,x2,|x|, x^2, and x4x^4 are continuous functions.
  • Differentiability: f(x)f(x) is differentiable everywhere. Though the absolute value function x|x| has a non-differentiable point at x=0x = 0, the combination f(x)=x+x2+x4f(x) = |x| + x^2 + x^4 remains differentiable at x=0x = 0 due to the smoothness added by the x2x^2 and x4x^4 terms.

4. Graph and Monotonicity

  • For x0x \geq 0: f(x)=x+x2+x4f(x) = x + x^2 + x^4 is strictly increasing since each term x,x2,x4x, x^2, x^4 is increasing.

  • For x<0x < 0: f(x)=x+x2+x4f(x) = -x + x^2 + x^4. Even though x-x is positive and decreasing, x2+x4x^2 + x^4 increases faster as xx moves away from zero. Hence, f(x)f(x) also increases.

5. Conclusion

The function f(x)=x+x2+x4f(x) = |x| + x^2 + x^4 is:

  • Continuous and differentiable for all xx.
  • Strictly increasing for all xx due to the dominating terms x2x^2 and x4x^4.

Summary

f(x)=x+x2+x4f(x) = |x| + x^2 + x^4 is a smooth, strictly increasing function that is positive for all real numbers.

Would you like to see the detailed graph of this function or have any specific questions about its properties?

Additional Questions:

  1. How does the graph of f(x)=x+x2+x4f(x) = |x| + x^2 + x^4 look for different ranges of xx?
  2. What are the derivatives of f(x)=x+x2+x4f(x) = |x| + x^2 + x^4 for x0x \geq 0 and x<0x < 0?
  3. How would the function change if one of the terms were removed, such as x4x^4?
  4. Can we determine the concavity of f(x)f(x) over its domain?
  5. What is the limit of f(x)f(x) as xx approaches infinity or negative infinity?

Tip: When analyzing functions involving absolute values, consider breaking down the function into cases for positive and negative xx to understand its behavior fully.

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Math Problem Analysis

Mathematical Concepts

Absolute value function
Polynomial functions
Function continuity
Function differentiability
Function monotonicity

Formulas

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Theorems

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Suitable Grade Level

Advanced High School