Math Problem Statement

Determine which of the following graphs G1 and G2 represents Eulerian circuit, Eulerian path, Hamiltonian circuit and Hamiltonian path. Justify your answer.

Solution

To determine whether the graphs G1G1 and G2G2 represent an Eulerian circuit, Eulerian path, Hamiltonian circuit, and Hamiltonian path, let's analyze each case systematically.


1. Eulerian Circuit and Eulerian Path

  • Conditions for Eulerian Circuit: All vertices must have even degrees.
  • Conditions for Eulerian Path: Exactly 0 or 2 vertices can have odd degrees.

Graph G1G1:

  • Degrees of vertices:

    • A:2,B:2,C:3,D:4,E:2,F:2,G:3A: 2, B: 2, C: 3, D: 4, E: 2, F: 2, G: 3.
  • Odd degree vertices: CC and GG (2 vertices).

    Conclusion:

    • G1G1 does not have an Eulerian circuit (due to odd-degree vertices).
    • G1G1 has an Eulerian path (exactly 2 vertices have odd degrees).

Graph G2G2:

  • Degrees of vertices:

    • a:2,b:3,c:3,d:4,e:2,f:2,g:3,h:2a: 2, b: 3, c: 3, d: 4, e: 2, f: 2, g: 3, h: 2.
  • Odd degree vertices: b,c,gb, c, g (3 vertices).

    Conclusion:

    • G2G2 does not have an Eulerian circuit (odd-degree vertices).
    • G2G2 does not have an Eulerian path (more than 2 odd-degree vertices).

2. Hamiltonian Circuit and Hamiltonian Path

  • Conditions for Hamiltonian Circuit: A closed path visits every vertex exactly once and returns to the starting vertex.
  • Conditions for Hamiltonian Path: A path visits every vertex exactly once (no need to return to the starting vertex).

Graph G1G1:

  • G1G1 has a Hamiltonian path: ABEGFDCA \to B \to E \to G \to F \to D \to C.
  • G1G1 does not have a Hamiltonian circuit because no single closed path covers all vertices.

Graph G2G2:

  • G2G2 has a Hamiltonian path: abehgfcda \to b \to e \to h \to g \to f \to c \to d.
  • G2G2 does not have a Hamiltonian circuit because no single closed path covers all vertices.

Summary

Graph G1G1:

  • Eulerian Circuit: No
  • Eulerian Path: Yes
  • Hamiltonian Circuit: No
  • Hamiltonian Path: Yes

Graph G2G2:

  • Eulerian Circuit: No
  • Eulerian Path: No
  • Hamiltonian Circuit: No
  • Hamiltonian Path: Yes

Would you like further clarifications or detailed visualizations for these explanations?

Here are five related questions for deeper understanding:

  1. What are the mathematical proofs behind the conditions for Eulerian circuits and paths?
  2. How does the degree of vertices affect the existence of Hamiltonian paths?
  3. Can we generalize these findings for directed graphs?
  4. Are there algorithms to find Eulerian paths or Hamiltonian paths systematically?
  5. What are some real-world applications of these graph theories?

Tip: Always start by determining vertex degrees when analyzing graph problems—it simplifies identifying paths and circuits.

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Math Problem Analysis

Mathematical Concepts

Graph Theory
Eulerian Circuit and Path
Hamiltonian Circuit and Path

Formulas

Eulerian Circuit: All vertices have even degree.
Eulerian Path: Exactly 0 or 2 vertices have odd degree.

Theorems

Degree theorem for Eulerian paths and circuits
Hamiltonian path and circuit conditions

Suitable Grade Level

Undergraduate level