I see that you've uploaded a graph worksheet. Let me break it down and provide insights to help complete it:

Analysis of the Graph:

• Increasing Interval(s): The graph is increasing from $x = -3$ to $x = 0$.
  Interval: $(-3, 0)$

• Decreasing Interval(s): The graph is decreasing for $x < -3$ and for $x > 0$.
  Intervals: $(-\infty, -3)$ and $(0, \infty)$

• X-intercept(s)/Roots/Solutions/Zeros: The graph crosses the $x$-axis at two points, approximately at $x = -4$ and $x = 2$. These are the zeros.

• End Behavior:

  • As $x \to -\infty$, $f(x) \to -\infty$
  • As $x \to \infty$, $f(x) \to -\infty$
    This is consistent with the graph of a parabola opening downwards.

• Domain: The graph continues indefinitely along the $x$-axis.
  Domain: $(-\infty, \infty)$

• Range: The highest point of the parabola (its vertex) appears to be at approximately $y = 4$.
  Range: $(-\infty, 4]$

Would you like more help with completing this or additional clarification?

Here are some related questions to expand your understanding:

1. What is the formula for this quadratic function?
2. How can you find the exact vertex of the parabola?
3. Why does the domain of this function cover all real numbers?
4. What would happen to the end behavior if the parabola opened upwards?
5. How can you confirm the exact values of the x-intercepts algebraically?

Tip: For any parabola, the vertex form $f(x) = a(x - h)^2 + k$ helps quickly identify the vertex $(h, k)$.