The equation in the image is:

$y = -4 \sin \left( 2x + \frac{\pi}{3} \right)$

Amplitude:

The amplitude of a sine function is determined by the coefficient in front of the sine. Here, the coefficient is $-4$. The amplitude is always the positive value of this coefficient, so the amplitude is:

$\text{Amplitude} = 4$

Period:

The period of a sine function is given by the formula:

$\text{Period} = \frac{2\pi}{|B|}$

where $B$ is the coefficient of $x$ in the sine function. In this case, $B = 2$. Therefore, the period is:

$\text{Period} = \frac{2\pi}{2} = \pi$

So, the amplitude is 4, and the period is $\pi$.

Do you need further explanation or details on this topic? Here are a few related questions you might find interesting:

1. How does changing the coefficient of $x$ affect the period of a sine wave?
2. What is the effect of the phase shift in the sine function on its graph?
3. How do you identify the amplitude and period from the general form of the sine function?
4. Can you graph a sine function with a negative amplitude?
5. What happens to the sine function if the coefficient in front of the sine is positive?

Tip: Remember, the amplitude is always the absolute value of the coefficient in front of the sine, while the period is affected by the coefficient of $x$.