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The question asks to determine the period and amplitude of the function \( y = 3 \sin\left(2x + \frac{\pi}{4}\right) \).

### 1. **Amplitude**:
The amplitude of a sinusoidal function \( y = a \sin(bx + c) \) is given by the absolute value of the coefficient of the sine function. In this case, the amplitude is:
\[
\text{Amplitude} = |a| = |3| = 3
\]

### 2. **Period**:
The period of a sine function \( y = a \sin(bx + c) \) is determined by the coefficient \( b \) in front of the \( x \). The formula for the period is:
\[
\text{Period} = \frac{2\pi}{|b|}
\]
In this function, \( b = 2 \). Therefore, the period is:
\[
\text{Period} = \frac{2\pi}{2} = \pi
\]

### Final Answer:
- **Amplitude**: \( 3 \)
- **Period**: \( \pi \)

Let me know if you'd like further details or if you have any other questions!

### Related Questions:
1. How does the phase shift affect the graph of \( y = 3 \sin(2x + \frac{\pi}{4}) \)?
2. How would the amplitude and period change if the equation was \( y = 5 \sin(3x) \)?
3. What is the effect of the coefficient of \( x \) on the frequency of the sine function?
4. Can you sketch the graph of \( y = 3 \sin(2x + \frac{\pi}{4}) \)?
5. How does the period of \( \cos(x) \) compare to that of \( \sin(x) \)?

### Tip:
The phase shift of a sine or cosine function is calculated by \( -\frac{c}{b} \) when the function is of the form \( a \sin(bx + c) \). This tells how far the graph is horizontally shifted.

Tentukan periode dan amplitudo dari fungsi y = 3sin(2x + π/4).

Learn how to calculate the amplitude and period of the trigonometric function y = 3sin(2x + π/4). This solution covers key trigonometric concepts, including the formula for amplitude and period of sinusoidal functions, suitable for students in Grades 10-12.

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