Math Problem Statement
Question 3 The numbers in the table below are the result of executing an algorithm that has one parameter N, a non-negative integer, and produces sequences of integers as outputs. For values of N from 0 to 5, the algorithm produces the following sequences of numbers as outputs:
N
output
0
1
-1 0 3
2
-4 -3 0 5 12 21
3
-9 -8 -5 0 7 16 27 40 55
4
-16 -15 -12 -7 0 9 20 33 48 65 84 105
5
-25 -24 -21 -16 -9 0 11 24 39 56 75 96 119 144 171
Determine the algorithm that was used to generate the numbers in this table, and
Write it down.
Execute it for N = 6, and write down your result.
What is the sequence of numbers for N = 6?
(Give your answer as integers separated by single spaces.)
Solution
Step-by-Step Breakdown
We are tasked with determining the algorithm that generates the sequence based on values of . Let's analyze the sequences:
-
For :
Sequence: -
For :
Sequence: -
For :
Sequence: -
For :
Sequence: -
For :
Sequence: -
For :
Sequence:
Observing the Pattern:
- The sequence length increases with , starting with 1 element for , 3 elements for , 6 elements for , and so on.
- The number of terms in each sequence follows the pattern:
- : 1 term
- : 3 terms
- : 6 terms
- : 9 terms
- : 12 terms
- : 15 terms
- So, the number of terms for seems to be .
Relationship between terms:
The sequences seem to follow a second-order difference pattern. The differences between consecutive terms can be analyzed:
-
For , the differences are:
-
For , the differences are:
-
For , the differences are:
This shows a pattern where the differences between terms increase by 2 each time. Specifically, the differences follow the sequence: 1, 3, 5, 7, 9, 11, etc.
General Algorithm:
- Start with the first number .
- Each subsequent number is generated by adding an increasing odd number to the previous number.
Algorithm for :
Following the same pattern:
- Start with .
- The number of terms will be .
- Generate the terms by adding the differences 1, 3, 5, 7, etc.
Let's compute the sequence.
Calculating the sequence for :
a_1 &= -36, \\ a_2 &= -36 + 1 = -35, \\ a_3 &= -35 + 3 = -32, \\ a_4 &= -32 + 5 = -27, \\ a_5 &= -27 + 7 = -20, \\ a_6 &= -20 + 9 = -11, \\ a_7 &= -11 + 11 = 0, \\ a_8 &= 0 + 13 = 13, \\ a_9 &= 13 + 15 = 28, \\ a_{10} &= 28 + 17 = 45, \\ a_{11} &= 45 + 19 = 64, \\ a_{12} &= 64 + 21 = 85, \\ a_{13} &= 85 + 23 = 108, \\ a_{14} &= 108 + 25 = 133, \\ a_{15} &= 133 + 27 = 160, \\ a_{16} &= 160 + 29 = 189, \\ a_{17} &= 189 + 31 = 220, \\ a_{18} &= 220 + 33 = 253, \\ a_{19} &= 253 + 35 = 288. \end{aligned}$$ Thus, the sequence for $$N = 6$$ is: $$-36 -35 -32 -27 -20 -11 0 13 28 45 64 85 108 133 160 189 220 253 288$$ ### Final Answer: The sequence of numbers for $$N = 6$$ is: $$-36 -35 -32 -27 -20 -11 0 13 28 45 64 85 108 133 160 189 220 253 288$$ Would you like more details, or do you have any further questions? --- Here are 5 related questions to explore further: 1. What is the general formula for generating terms for any $$N$$? 2. How would the pattern change if the differences increased by 3 instead of 2? 3. Can you express the position of any term in the sequence as a function of $$N$$? 4. What happens to the sequence if you start from a different initial term? 5. How can you modify this sequence to follow a geometric progression instead? **Tip:** Always look for patterns in differences between terms to discover hidden rules in sequences.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Number Sequences
Difference Sequences
Patterns
Formulas
First term: a_1 = -N^2
Next term: a_n = a_(n-1) + (2n - 1)
Theorems
Arithmetic Sequence
Second-Order Difference Sequence
Suitable Grade Level
Grades 10-12
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