Math Problem Statement

in figure 1 there is one piece , in figure 2 there are 3 pieces , in figure 3 there are 6 pieces and in figure 4 there are 10 pieces Create an algebraic expression for the number of pieces in figure n create the formula too and show how you created the formula

Solution

To create an algebraic expression for the number of pieces in figure nn, let's analyze the pattern:

  • Figure 1: 1 piece
  • Figure 2: 3 pieces
  • Figure 3: 6 pieces
  • Figure 4: 10 pieces

We need to find a relationship between the figure number nn and the number of pieces.

Step 1: Identify the Pattern

Let's list the number of pieces:

  • 1,3,6,10,1, 3, 6, 10, \dots

These numbers look like triangular numbers, which are generated by summing the first nn natural numbers:

  • T1=1T_1 = 1
  • T2=1+2=3T_2 = 1 + 2 = 3
  • T3=1+2+3=6T_3 = 1 + 2 + 3 = 6
  • T4=1+2+3+4=10T_4 = 1 + 2 + 3 + 4 = 10

So, the number of pieces in figure nn corresponds to the nn-th triangular number.

Step 2: Formula for Triangular Numbers

The formula for the nn-th triangular number TnT_n is given by:

Tn=n(n+1)2T_n = \frac{n(n + 1)}{2}

This formula represents the sum of the first nn natural numbers.

Step 3: General Formula for Number of Pieces

Thus, the number of pieces in figure nn is:

P(n)=n(n+1)2P(n) = \frac{n(n + 1)}{2}

Where:

  • P(n)P(n) represents the number of pieces in figure nn,
  • nn is the figure number.

Step 4: Verification

Let’s check this formula for the given figures:

  • Figure 1: P(1)=1(1+1)2=1×22=1P(1) = \frac{1(1 + 1)}{2} = \frac{1 \times 2}{2} = 1
  • Figure 2: P(2)=2(2+1)2=2×32=3P(2) = \frac{2(2 + 1)}{2} = \frac{2 \times 3}{2} = 3
  • Figure 3: P(3)=3(3+1)2=3×42=6P(3) = \frac{3(3 + 1)}{2} = \frac{3 \times 4}{2} = 6
  • Figure 4: P(4)=4(4+1)2=4×52=10P(4) = \frac{4(4 + 1)}{2} = \frac{4 \times 5}{2} = 10

The formula works correctly for the provided figures.

Final Formula:

P(n)=n(n+1)2P(n) = \frac{n(n + 1)}{2}

This is the algebraic expression for the number of pieces in figure nn.


Would you like more details on how triangular numbers work, or do you have any specific questions?

5 Related Questions:

  1. How do you derive the formula for the sum of the first nn natural numbers?
  2. Can this formula be used for non-integer values of nn?
  3. What are some real-world applications of triangular numbers?
  4. How does the growth rate of triangular numbers compare to square or cubic numbers?
  5. Can we generalize this to other patterns of shapes besides triangles?

Tip:

Always verify your formula by checking it with specific values to ensure accuracy.

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Math Problem Analysis

Mathematical Concepts

Triangular Numbers

Formulas

Triangular number formula T_n = n(n + 1)/2

Theorems

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Suitable Grade Level

Grades 7-9