Math Problem Statement

If e can be written as a+c/d also the value of a is b+c/d and value of b is a+c/d .how can we write it and what will be the final value of e.

Solution

To solve this, let's carefully analyze the information given:

  1. ee can be written as: e=a+cde = \frac{a + c}{d}

  2. The value of aa is: a=b+cda = \frac{b + c}{d}

  3. The value of bb is: b=a+cdb = \frac{a + c}{d}

We need to find the value of ee. To do that, we can use substitution. Notice that from the given equations, both ee and bb are expressed as a+cd\frac{a + c}{d}. This means: e=be = b

Now let's substitute the expression for bb from the third equation: b=a+cdb = \frac{a + c}{d} We have: e=a+cde = \frac{a + c}{d}

Since ee and aa are related, we substitute the expression for aa from the second equation: a=b+cda = \frac{b + c}{d} Now, using the fact that b=eb = e, we substitute again: a=e+cda = \frac{e + c}{d}

We already have e=a+cde = \frac{a + c}{d}, so let's substitute the value of aa we found: e=e+cd+cde = \frac{\frac{e + c}{d} + c}{d}

To simplify, let's multiply both the numerator and the denominator by dd to eliminate the fractions: e=e+c+cdd2e = \frac{e + c + cd}{d^2}

Now, we rearrange the equation to isolate ee: ed2=e+c+cde \cdot d^2 = e + c + cd ed2e=c+cde \cdot d^2 - e = c + cd e(d21)=c(d+1)e(d^2 - 1) = c(d + 1)

Finally, we can express ee as: e=c(d+1)d21e = \frac{c(d + 1)}{d^2 - 1}

This is the simplified final value of ee.

Would you like further details or clarification on any of these steps? Here are 5 related questions you might find helpful:

  1. How do you solve similar equations by substitution?
  2. What happens if cc or dd equals zero in this expression?
  3. Can this process be used to solve for aa and bb directly as well?
  4. How does the simplification of fractions work in multi-step problems?
  5. What are common scenarios where circular dependencies like this one appear?

Tip: When faced with multiple equations where variables depend on each other, substitution and rearrangement are key strategies to isolate and solve for each variable.

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Math Problem Analysis

Mathematical Concepts

Algebra
Substitution Method
Equation Solving

Formulas

e = (a + c) / d
a = (b + c) / d
b = (a + c) / d
e = (c(d + 1)) / (d^2 - 1)

Theorems

Substitution Theorem
Algebraic Manipulation

Suitable Grade Level

Grades 9-11