To add these numbers, we first need to deal with them as mixed numbers and fractions. Let's break it down:

The numbers are:

1. $65 \frac{3}{16}$
2. $64 \frac{1}{16}$
3. $63$
4. $66$
5. $65 \frac{1}{8}$
6. $65 \frac{3}{4}$
7. $65 \frac{3}{4}$
8. $65 \frac{34}{16}$ (this seems unusual, but we'll convert $\frac{34}{16}$ to $2 \frac{2}{16} = 2 \frac{1}{8}$)
9. $65 \frac{9}{16}$
10. $64 \frac{7}{8}$
11. $67 \frac{1}{16}$

Step-by-step:

1. Convert the mixed numbers to improper fractions where possible.
2. Add the whole numbers and fractions separately.

Let's start by adding the whole numbers: $65 + 64 + 63 + 66 + 65 + 65 + 65 + 65 + 64 + 67 = 615$

Now let's add the fractions:

1. $\frac{3}{16} + \frac{1}{16} + 0 + 0 + \frac{1}{8} + \frac{3}{4} + \frac{3}{4} + \frac{1}{8} + \frac{9}{16} + \frac{7}{8} + \frac{1}{16}$

Let's combine the fractions step by step:

• First, convert everything to 16ths:

  • $\frac{1}{8} = \frac{2}{16}$
  • $\frac{3}{4} = \frac{12}{16}$
  • $\frac{7}{8} = \frac{14}{16}$

• Now, add all the fractions: $\frac{3}{16} + \frac{1}{16} + 0 + 0 + \frac{2}{16} + \frac{12}{16} + \frac{12}{16} + \frac{2}{16} + \frac{9}{16} + \frac{14}{16} + \frac{1}{16}$ $= \frac{3+1+2+12+12+2+9+14+1}{16} = \frac{56}{16} = 3 \frac{8}{16} = 3 \frac{1}{2}$

Now, combining the whole numbers and the fraction:

• Whole numbers: 615
• Fractions: $3 \frac{1}{2}$

So, the total sum is: $615 + 3 \frac{1}{2} = 618 \frac{1}{2}$

Thus, the sum of all the numbers is 618 1/2.

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Would you like any further breakdown or details on the process? Here are some related questions for you:

1. How do you add mixed fractions with different denominators?
2. Can you convert a fraction to a decimal, and why would you want to?
3. How do you simplify fractions, like when you get $\frac{56}{16}$?
4. What is the importance of finding a common denominator when adding fractions?
5. How can you check your work when adding mixed numbers?

Tip: When dealing with mixed numbers, always try to convert them to improper fractions first if you are unfamiliar with directly adding them.