The problem states:

McKenna spends $\frac{7}{4}$ hours mopping the floors and $\frac{27}{8}$ hours mowing and weeding the yard. How many hours does she spend on her chores?

Step 1: Add the fractions

To add $\frac{7}{4}$ and $\frac{27}{8}$, we first need a common denominator.

The denominators are 4 and 8. The least common denominator (LCD) is 8.

• Rewrite $\frac{7}{4}$ as an equivalent fraction with a denominator of 8: $\frac{7}{4} = \frac{14}{8}$

Now the problem is: $\frac{14}{8} + \frac{27}{8}$

Step 2: Add the numerators

Since the denominators are the same, add the numerators: $\frac{14}{8} + \frac{27}{8} = \frac{41}{8}$

Step 3: Convert to a mixed number (if needed)

Divide the numerator (41) by the denominator (8): $41 \div 8 = 5 \text{ remainder } 1$

So: $\frac{41}{8} = 5 \frac{1}{8}$

Final Answer:

McKenna spends $5 \frac{1}{8}$ hours on her chores.

Would you like additional details or explanations?

Here are 5 related questions for further practice:

1. How would you subtract $\frac{27}{8}$ from $\frac{7}{4}$?
2. What is $\frac{41}{8}$ as a decimal?
3. If McKenna worked an additional $\frac{5}{8}$ hours, what would her total chore time be?
4. How do you find the least common denominator (LCD) of two fractions?
5. Can you simplify $\frac{7}{4}$ further before adding it to another fraction?

Tip: When adding or subtracting fractions, always check if the denominators are the same; if not, find the least common denominator.