Math Problem Statement

Paul walked 4/5 of a mile from school to Evelyn's house and 2/5 of a mile from Evelyn's house to his own house. How many miles did Paul walk in all?

Solution

The problem states:

Paul walked 45\frac{4}{5} of a mile from school to Evelyn's house and 25\frac{2}{5} of a mile from Evelyn's house to his own house. How many miles did Paul walk in all?

To find the total distance Paul walked, we need to add the two fractions:

45+25\frac{4}{5} + \frac{2}{5}

Since the fractions have the same denominator, we can simply add the numerators:

4+25=65\frac{4 + 2}{5} = \frac{6}{5}

The fraction 65\frac{6}{5} can be written as a mixed number:

65=115\frac{6}{5} = 1 \frac{1}{5}

Answer:

Paul walked 65\frac{6}{5} miles, or 1151 \frac{1}{5} miles in total.

Would you like further details or have any questions about this solution?


Here are 5 related questions to deepen understanding:

  1. How would the answer change if Paul walked 35\frac{3}{5} of a mile from Evelyn's house to his own house?
  2. What would be the result if Paul walked 55\frac{5}{5} of a mile each way?
  3. How can you add fractions with different denominators?
  4. How would you convert 65\frac{6}{5} to a decimal?
  5. What is the difference in distance if he walked back from his house to Evelyn’s again?

Tip: When adding fractions, make sure they have the same denominator before adding the numerators.

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Math Problem Analysis

Mathematical Concepts

Fractions
Addition of Fractions
Mixed Numbers

Formulas

Addition of fractions with common denominators

Theorems

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Suitable Grade Level

Grade 5