To solve the problem $(5 - 2i) + (3 + 3i)$ and write the result in standard form:

Step 1: Add the real parts

$5 + 3 = 8$

Step 2: Add the imaginary parts

$-2i + 3i = i$

Step 3: Combine both

The result is: $8 + i$

Thus, the result in standard form is $8 + i$.

Would you like more details or have any questions about this?

Here are 5 related questions for further practice:

1. What is the result of $(6 - 4i) + (2 + 5i)$?
2. How do you subtract complex numbers like $(7 + 3i) - (4 + 2i)$?
3. How can you multiply complex numbers $(2 + i)(3 - 2i)$?
4. What is the standard form of the complex number $4i$?
5. How do you calculate the modulus of a complex number $z = 8 + i$?

Tip: When adding or subtracting complex numbers, always group and handle real and imaginary parts separately.