f(x)	 = 	7x − 1 f(x)	 
g(x)	 = 	x2 − 8x − 7
 (f + g)(x)


To find \((f + g)(x)\), we need to add the functions \(f(x)\) and \(g(x)\).

Given:
- \( f(x) = 7x - 1 \)
- \( g(x) = x^2 - 8x - 7 \)

Now, let's calculate \((f + g)(x)\):

\[
(f + g)(x) = f(x) + g(x)
\]
\[
(f + g)(x) = (7x - 1) + (x^2 - 8x - 7)
\]

Now combine like terms:

\[
(f + g)(x) = x^2 + (7x - 8x) - 1 - 7
\]
\[
(f + g)(x) = x^2 - x - 8
\]

So, \((f + g)(x) = x^2 - x - 8\).

Would you like further details or have any questions?

Here are 5 related questions to explore:
1. What is \((f - g)(x)\) using the same functions?
2. How do you find \((f \cdot g)(x)\)?
3. What is the derivative of \((f + g)(x)\)?
4. Can you evaluate \((f + g)(2)\)?
5. What is the domain of \((f + g)(x)\)?

**Tip:** When adding functions, always combine like terms carefully, especially when dealing with powers of \(x\).

f(x) = 7x − 1, g(x) = x^2 − 8x − 7, (f + g)(x)

Learn how to find the sum of two functions, f(x) = 7x - 1 and g(x) = x^2 - 8x - 7, by performing polynomial addition. This detailed solution walks through the steps of combining like terms and presents the final result for (f + g)(x). Ideal for students in Grades 9-10.

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