Math Problem Statement

Two forces F1 = 5.0 N î + 7.0 N ĵ and F2 = -3.0 N î + 8.0 N ĵ are applied to a 0.25 kg particle. What is the acceleration vector of the particle?

Solution

To solve this problem, let's calculate the net force applied to the particle and then use Newton's second law (F=maF = ma) to determine the acceleration.

Step 1: Calculate the net force

The two forces are given as: F1=5.0i^+7.0j^N\mathbf{F}_1 = 5.0 \, \mathbf{\hat{i}} + 7.0 \, \mathbf{\hat{j}} \, \text{N} F2=3.0i^+8.0j^N\mathbf{F}_2 = -3.0 \, \mathbf{\hat{i}} + 8.0 \, \mathbf{\hat{j}} \, \text{N}

The net force is: Fnet=F1+F2\mathbf{F}_{\text{net}} = \mathbf{F}_1 + \mathbf{F}_2 [ \mathbf{F}_{\text{net}} = (5.0 - 3.0) , \mathbf{\hat{i}} + (7

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Math Problem Analysis

Mathematical Concepts

Vector Addition
Newton's Second Law
Basic Algebra

Formulas

F_net = F1 + F2
F = ma

Theorems

Newton's Second Law

Suitable Grade Level

Grades 9-12