Math Problem Statement

A ball rolls around 25m for 10 seconds, so the acceleration of the ball is..

Solution

To find the acceleration of the ball, we can use the formula for acceleration, which is defined as the change in velocity divided by the time taken:

a=ΔvΔta = \frac{\Delta v}{\Delta t}

However, in this case, we are not given the initial or final velocities directly. Instead, we are given the distance traveled and the time taken. Assuming the ball starts from rest and accelerates uniformly, we can use the following kinematic equation to find the acceleration:

s=ut+12at2s = ut + \frac{1}{2} a t^2

where:

  • s=25ms = 25 \, \text{m} (distance traveled),
  • u=0m/su = 0 \, \text{m/s} (initial velocity, since it starts from rest),
  • t=10secondst = 10 \, \text{seconds} (time taken),
  • aa is the acceleration.

Substituting the known values into the equation:

25=0×10+12a(102)25 = 0 \times 10 + \frac{1}{2} a (10^2)

Simplifying:

25=12a×10025 = \frac{1}{2} a \times 100

25=50a25 = 50a

a=2550=0.5m/s2a = \frac{25}{50} = 0.5 \, \text{m/s}^2

So, the acceleration of the ball is 0.5m/s20.5 \, \text{m/s}^2.

Would you like more details or have any questions?

Here are 5 related questions you might find interesting:

  1. What is the velocity of the ball after 10 seconds?
  2. How would the acceleration change if the ball traveled 50 meters in the same time?
  3. What would happen if the ball had an initial velocity of 2 m/s?
  4. How would friction affect the acceleration of the ball?
  5. Can you calculate the force acting on the ball if its mass is 2 kg?

Tip: When dealing with uniformly accelerated motion, remember that kinematic equations are very useful for finding unknown quantities like acceleration, distance, or time.

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Math Problem Analysis

Mathematical Concepts

Kinematics
Uniformly Accelerated Motion

Formulas

s = ut + \frac{1}{2}at^2

Theorems

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Suitable Grade Level

Grades 9-12