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Let's break down the problem step by step, using the equations of motion under uniform acceleration.

### Given Information:
1. The car covers **250 m in 5.0 s** in the first part.
2. The car covers the next **250 m in 3.0 s**.

We need to find the **acceleration** of the car.

### Step 1: Finding the initial velocity \( v_{i1} \) for the first 250 m (using 5.0 s).

We'll use the equation of motion:
\[
s = v_i t + \frac{1}{2} a t^2
\]
Where:
- \( s = 250 \, \text{m} \)
- \( t = 5.0 \, \text{s} \)
- \( v_i \) is the initial velocity for the first section
- \( a \) is the acceleration (unknown)

This equation has two unknowns: \( v_i \) and \( a \). But we can get another equation from the second part of the motion.

### Step 2: Finding the final velocity \( v_{f1} \) at the end of the first 250 m.

Using the kinematic equation:
\[
v_f = v_i + a t
\]
At the end of 5.0 s, the velocity changes from \( v_{i1} \) to \( v_{f1} \).

### Step 3: Finding the velocity and acceleration from the second 250 m.

For the second part (next 250 m in 3.0 s), we have:
- Initial velocity = \( v_{f1} \) (which is the final velocity from the first section)
- Time = 3.0 s
- Distance = 250 m

We can again use the same kinematic equations to form another system of equations

A uniformly accelerated car takes 5.0 s to cover 250 m and another 3.0 s to cover the next 250 m. Find the acceleration of the car.

Learn how to calculate the acceleration of a car that covers 250 m in 5.0 seconds and another 250 m in 3.0 seconds. This problem involves using the equations of motion under uniform acceleration, suitable for students in Grades 10-12.

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