Let's go through each question step-by-step to solve the problems presented in your quiz.

Question 1:

Given the AC signal graph, we need to determine:

a. The frequency and the peak-to-peak voltage for signal A.

From the graph:

• The time period $T$ can be found by looking at the duration between two consecutive peaks or two zero-crossings in the same direction.
• From the graph, it appears that the period $T$ is approximately 2 milliseconds (ms).

Using the formula: $f = \frac{1}{T}$ where $T = 2 \, \text{ms} = 0.002 \, \text{s}$, we get: $f = \frac{1}{0.002} = 500 \, \text{Hz}$

To determine the peak-to-peak voltage:

• The graph shows the signal amplitude varying from $0$ to approximately $10$ V, meaning the peak-to-peak voltage is $10 \, \text{V}$.

Answer for 1(a):

• Frequency: 500 Hz
• Peak-to-peak Voltage: 10 V

b. Is signal A leading or lagging signal B?

From the graph, signal A reaches a peak before signal B. This indicates that signal A is leading signal B.

Answer for 1(b):

• Signal A is leading signal B.

Question 2:

Determine the total capacitance for both circuits.

For capacitors:

1. In series: The total capacitance $C_{total}$ is given by: $\frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2}$

2. In parallel: The total capacitance $C_{total}$ is given by: $C_{total} = C_1 + C_2$

Left Circuit:

• Capacitance in series: (