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Let's go through each question step-by-step to solve the problems presented in your quiz.

### Question 1:
Given the AC signal graph, we need to determine:

**a. The frequency and the peak-to-peak voltage for signal A.**

From the graph:
- The time period \( T \) can be found by looking at the duration between two consecutive peaks or two zero-crossings in the same direction.
- From the graph, it appears that the period \( T \) is approximately 2 milliseconds (ms).

Using the formula:
\[
f = \frac{1}{T}
\]
where \( T = 2 \, \text{ms} = 0.002 \, \text{s} \), we get:
\[
f = \frac{1}{0.002} = 500 \, \text{Hz}
\]

To determine the peak-to-peak voltage:
- The graph shows the signal amplitude varying from \( 0 \) to approximately \( 10 \) V, meaning the peak-to-peak voltage is \( 10 \, \text{V} \).

**Answer for 1(a):**
- **Frequency**: 500 Hz
- **Peak-to-peak Voltage**: 10 V

**b. Is signal A leading or lagging signal B?**

From the graph, signal A reaches a peak before signal B. This indicates that **signal A is leading signal B**.

**Answer for 1(b):**
- **Signal A is leading signal B.**

---

### Question 2:
Determine the total capacitance for both circuits.

For capacitors:
1. **In series**: The total capacitance \( C_{total} \) is given by:
   \[
   \frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2}
   \]

2. **In parallel**: The total capacitance \( C_{total} \) is given by:
   \[
   C_{total} = C_1 + C_2
   \]

**Left Circuit**:
- Capacitance in series: \(

1. Given the AC signal below, determine: 
   a. The frequency and the peak-to-peak voltage for signal A. 
   b. Is signal A leading or lagging signal B?

2. Determine the total capacitance for both circuits.

3. Determine the capacitor voltage after 1.5 ms of closing the switch. Assume capacitor is fully discharged just before closing the switch.

Solve AC circuit problems by calculating frequency and peak-to-peak voltage, determining total capacitance in series and parallel circuits, and finding capacitor voltage in an RC circuit after 1.5 ms. Suitable for high school students.

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