Math Problem Statement

|2x + 3| < 7

Solution

The inequality you've provided is:

2x+3<7|2x + 3| < 7

To solve this inequality, we follow these steps:

Step 1: Break it into two inequalities

Since the absolute value of an expression A<B|A| < B implies that B<A<B-B < A < B, we can rewrite the inequality as:

7<2x+3<7-7 < 2x + 3 < 7

Step 2: Solve each part of the compound inequality

Solve the left inequality:

7<2x+3-7 < 2x + 3 Subtract 3 from both sides: 73<2x    10<2x-7 - 3 < 2x \implies -10 < 2x Now divide by 2: 102<x    5<x\frac{-10}{2} < x \implies -5 < x

Solve the right inequality:

2x+3<72x + 3 < 7 Subtract 3 from both sides: 2x<73    2x<42x < 7 - 3 \implies 2x < 4 Now divide by 2: x<42    x<2x < \frac{4}{2} \implies x < 2

Step 3: Combine the two results

We now have: 5<x<2-5 < x < 2

This means the solution to the inequality is: x(5,2)x \in (-5, 2)

Would you like further details or have any questions about this? Here are some related questions:

  1. How would you solve if the inequality was 2x+3>7|2x + 3| > 7?
  2. What happens if the absolute value inequality includes a "less than or equal to" (\leq) sign?
  3. How does solving absolute value inequalities differ from solving regular inequalities?
  4. How do absolute value inequalities apply in real-world scenarios?
  5. What if the inequality was 2x+3=7|2x + 3| = 7?

Tip: Always split absolute value inequalities into two parts and remember that both the positive and negative aspects need to be considered!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Absolute Value Inequalities

Formulas

|A| < B implies -B < A < B

Theorems

Properties of absolute value inequalities

Suitable Grade Level

Grades 9-11