Math Problem Statement

Write the absolute value function as a piecewise-defined function with linear parts. f(x) = |5x + 7|

Solution

You are asked to rewrite the absolute value function f(x)=5x+7f(x) = |5x + 7| as a piecewise-defined function with linear parts. To achieve this, we will split the absolute value function into two cases based on when the expression inside the absolute value is positive or negative.

Step-by-Step Solution:

The function f(x)=5x+7f(x) = |5x + 7| can be written as:

  1. When 5x+705x + 7 \geq 0 (i.e., x75x \geq -\frac{7}{5}): In this case, the absolute value of 5x+75x + 7 is just 5x+75x + 7. So, for x75x \geq -\frac{7}{5}, f(x)=5x+7f(x) = 5x + 7.

  2. When 5x+7<05x + 7 < 0 (i.e., x<75x < -\frac{7}{5}): In this case, the absolute value of 5x+75x + 7 is (5x+7)=5x7-(5x + 7) = -5x - 7. So, for x<75x < -\frac{7}{5}, f(x)=5x7f(x) = -5x - 7.

Piecewise-Defined Function:

\begin{cases} 5x + 7 & \text{if } x \geq -\frac{7}{5} \\ -5x - 7 & \text{if } x < -\frac{7}{5} \end{cases}$$ This is the absolute value function rewritten as a piecewise-defined function. Would you like any additional clarification, or do you have further questions on this? --- Here are 5 related questions to expand on this concept: 1. How do you graph the piecewise-defined function for $$f(x) = |5x + 7|$$? 2. Can you find the point where $$f(x) = |5x + 7|$$ intersects the x-axis? 3. How would the piecewise function change if it was $$f(x) = |3x - 4|$$ instead? 4. How do we solve $$|5x + 7| = 10$$? 5. What is the domain and range of the function $$f(x) = |5x + 7|$$? **Tip**: When dealing with absolute value functions, always consider breaking the function down into cases where the expression inside the absolute value is positive or negative.

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Math Problem Analysis

Mathematical Concepts

Piecewise Functions
Absolute Value Functions
Linear Functions

Formulas

f(x) = |ax + b| = { ax + b if x >= -b/a; -(ax + b) if x < -b/a }

Theorems

Definition of Absolute Value
Piecewise Function Definition

Suitable Grade Level

Grades 9-10