Math Problem Statement
Find the absolute extrema of f(x) =sin x on [0, π]
Solution
To find the absolute extrema (the maximum and minimum values) of the function on the interval , we need to follow these steps:
Step 1: Check the critical points
Critical points occur where the derivative of the function is either zero or undefined.
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First, find the derivative of :
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Set the derivative equal to zero to find critical points:
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Solve for within the interval : So, is a critical point within the interval .
Step 2: Evaluate the function at the endpoints of the interval and at the critical points
Now, we evaluate at the endpoints of the interval and at the critical point .
- At :
- At :
- At (the critical point):
Step 3: Identify the absolute maximum and minimum
From the evaluations above, we have:
The absolute maximum value of on the interval is , which occurs at , and the absolute minimum value is , which occurs at both and .
Final Answer:
- The absolute maximum value of on is at .
- The absolute minimum value of on is at and .
Would you like to go over the steps in more detail, or do you have any specific questions?
Related Questions:
- How does the derivative behave over the interval ?
- What would the extrema be for on the same interval?
- How do absolute extrema differ from local extrema?
- What would happen if the interval was ?
- Can we apply the same method to other trigonometric functions, like ?
Tip:
Remember that the critical points are where the derivative equals zero or is undefined. For continuous functions, such as sine and cosine, the extrema can only occur either at these critical points or the boundaries of the interval.
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Math Problem Analysis
Mathematical Concepts
Calculus
Trigonometry
Critical Points
Extrema
Formulas
f'(x) = cos(x)
f(x) = sin(x)
Theorems
First derivative test for extrema
Absolute extrema on a closed interval
Suitable Grade Level
Grades 11-12
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