Math Problem Statement

Using Lagrange multipliers find the absolute maximum and absolute minimum of f(x,y) = x2 − xy + y2 subject to the constraint x2 + y2 = 4

Solution

To find the absolute maximum and absolute minimum of the function f(x,y)=x2xy+y2f(x, y) = x^2 - xy + y^2 subject to the constraint x2+y2=4x^2 + y^2 = 4 using Lagrange multipliers, we follow these steps:

Step 1: Define the Lagrange function

The constraint is g(x,y)=x2+y24=0g(x, y) = x^2 + y^2 - 4 = 0.

The Lagrange function is: L(x,y,λ)=f(x,y)λ(g(x,y))=(x2xy+y2)λ(x2+y24)\mathcal{L}(x, y, \lambda) = f(x, y) - \lambda (g(x, y)) = (x^2 - xy + y^2) - \lambda (x^2 + y^2 - 4)

Step 2: Compute the partial derivatives

To find the critical points, we take the partial derivatives of L(x,y,λ)\mathcal{L}(x, y, \lambda) with respect to xx, yy, and λ\lambda, and set them equal to zero.

  1. Lx=2xyλ(2x)=0\frac{\partial \mathcal{L}}{\partial x} = 2x - y - \lambda(2x) = 0
  2. (

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Math Problem Analysis

Mathematical Concepts

Multivariable Calculus
Lagrange Multipliers
Constrained Optimization

Formulas

Lagrange function: 𝓛(x, y, λ) = f(x, y) - λ(g(x, y))
Partial derivatives of 𝓛(x, y, λ) with respect to x, y, and λ

Theorems

Lagrange Multiplier Theorem

Suitable Grade Level

Undergraduate Level (Calculus III)