Math Problem Statement

Give an example that every abelian group is not cyclic.

Solution

To show that not every abelian group is cyclic, let's use a counterexample.

Example: The Group Z2×Z2\mathbb{Z}_2 \times \mathbb{Z}_2

Consider the group G=Z2×Z2G = \mathbb{Z}_2 \times \mathbb{Z}_2, which is the direct product of two copies of the cyclic group Z2\mathbb{Z}_2.

  1. Elements of the group:
    The elements of GG are pairs (a,b)(a, b), where aa and bb are elements of Z2\mathbb{Z}_2. Since Z2={0,1}\mathbb{Z}_2 = \{0, 1\}, the group GG has the following elements: G={(0,0),(0,1),(1,0),(1,1)}G = \{(0, 0), (0, 1), (1, 0), (1, 1)\} This group has 4 elements.

  2. Abelian property:
    GG is abelian because the group operation (component-wise addition mod 2) is commutative: (a1,b1)+(a2,b2)=(a2,b2)+(a1,b1)for all(a1,b1),(a2,b2)G(a_1, b_1) + (a_2, b_2) = (a_2, b_2) + (a_1, b_1) \quad \text{for all} \quad (a_1, b_1), (a_2, b_2) \in G

  3. Cyclic property check:
    To be cyclic, there must exist an element gGg \in G such that all elements of GG can be written as powers of gg (or, in additive notation, multiples of gg).

    • Let’s check each element to see if it generates the entire group:
      • If g=(0,0)g = (0, 0), the only element you get is (0,0)(0, 0), which does not generate the whole group.
      • If g=(1,0)g = (1, 0), the possible multiples of gg are: (1,0),(1,0)+(1,0)=(0,0)(1, 0), (1, 0) + (1, 0) = (0, 0) So, it only generates {(0,0),(1,0)}\{(0, 0), (1, 0)\}, which is not the whole group.
      • Similarly, if g=(0,1)g = (0, 1), it only generates {(0,0),(0,1)}\{(0, 0), (0, 1)\}, not the whole group.
      • Finally, if g=(1,1)g = (1, 1), the multiples are: (1,1),(1,1)+(1,1)=(0,0)(1, 1), (1, 1) + (1, 1) = (0, 0) This only generates {(0,0),(1,1)}\{(0, 0), (1, 1)\}, which is also not the whole group.
  4. Conclusion:
    Since no single element generates all four elements of GG, this group is not cyclic. Therefore, Z2×Z2\mathbb{Z}_2 \times \mathbb{Z}_2 is an abelian group that is not cyclic.

This provides an example showing that not all abelian groups are cyclic.


Would you like more details or have any questions about this?

5 Related Questions:

  1. What is the difference between cyclic and abelian groups?
  2. Can you give an example of a cyclic abelian group?
  3. What is the structure of direct product groups like Z2×Z2\mathbb{Z}_2 \times \mathbb{Z}_2?
  4. How do you determine if a group is cyclic?
  5. Are all finite abelian groups cyclic?

Tip:

For finite abelian groups, the Fundamental Theorem of Finite Abelian Groups states that every finite abelian group is a direct product of cyclic groups, but not necessarily a single cyclic group.

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Math Problem Analysis

Mathematical Concepts

Group Theory
Abelian Groups
Cyclic Groups
Direct Product of Groups

Formulas

-

Theorems

Fundamental Theorem of Finite Abelian Groups

Suitable Grade Level

Undergraduate level (Abstract Algebra)