Math Problem Statement

Is Z12 isomorphic to the external direct product of Z6 and Z2?

Solution

Yes, Z12\mathbb{Z}_{12} is isomorphic to the external direct product of Z6×Z2\mathbb{Z}_6 \times \mathbb{Z}_2. To understand why, we can explore the properties of these two groups:

1. Group Structure of Z12\mathbb{Z}_{12}:

  • Z12\mathbb{Z}_{12} is the cyclic group of order 12, generated by the element 1 (mod 12). Every element of Z12\mathbb{Z}_{12} can be written as {0,1,2,,11}\{0, 1, 2, \dots, 11\}, and the group operation is addition modulo 12.

2. Group Structure of Z6×Z2\mathbb{Z}_6 \times \mathbb{Z}_2:

  • Z6\mathbb{Z}_6 is the cyclic group of order 6, with elements {0,1,2,3,4,5}\{0, 1, 2, 3, 4, 5\}, and the group operation is addition modulo 6.
  • Z2\mathbb{Z}_2 is the cyclic group of order 2, with elements {0,1}\{0, 1\}, and the group operation is addition modulo 2.
  • The external direct product Z6×Z2\mathbb{Z}_6 \times \mathbb{Z}_2 consists of pairs (a,b)(a, b), where aZ6a \in \mathbb{Z}_6 and bZ2b \in \mathbb{Z}_2. The group operation is component-wise addition modulo 6 and modulo 2, respectively.

3. Checking the Isomorphism:

  • To check if two groups are isomorphic, they must have the same order (number of elements) and an isomorphism must exist between their group structures.
  • The order of Z12\mathbb{Z}_{12} is 12.
  • The order of Z6×Z2\mathbb{Z}_6 \times \mathbb{Z}_2 is 6×2=126 \times 2 = 12.

Since both groups have the same number of elements, we need to check if their group structures are compatible. One way to check this is to verify if they are both cyclic and if they share the same group type.

  • Z12\mathbb{Z}_{12} is cyclic and generated by 1 mod 12.
  • Z6×Z2\mathbb{Z}_6 \times \mathbb{Z}_2 is also cyclic because the element (1,1)(1, 1) generates all 12 elements of the group.

Thus, the two groups are isomorphic. This is an example of the structure theorem for finite abelian groups, which implies that the cyclic group Z12\mathbb{Z}_{12} can be decomposed as a direct product of Z6\mathbb{Z}_6 and Z2\mathbb{Z}_2.

Conclusion:

Yes, Z12Z6×Z2\mathbb{Z}_{12} \cong \mathbb{Z}_6 \times \mathbb{Z}_2, meaning these two groups are isomorphic.

Would you like more details or have any questions? Here are some related questions you might explore:

  1. How do you construct an explicit isomorphism between Z12\mathbb{Z}_{12} and Z6×Z2\mathbb{Z}_6 \times \mathbb{Z}_2?
  2. What is the structure theorem for finite abelian groups?
  3. Can you provide another example of two isomorphic groups?
  4. Is Z12\mathbb{Z}_{12} isomorphic to Z4×Z3\mathbb{Z}_4 \times \mathbb{Z}_3?
  5. How does the decomposition of a group as a direct product affect its subgroups?

Tip: When trying to establish an isomorphism between groups, always check both the group orders and the generators to ensure compatibility in structure.

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Math Problem Analysis

Mathematical Concepts

Group Theory
Cyclic Groups
Direct Products
Isomorphism
Finite Abelian Groups

Formulas

-

Theorems

Structure Theorem for Finite Abelian Groups

Suitable Grade Level

Undergraduate