Math Problem Statement
A country's education department reported that in 2015, 63.8% of students enrolled in college or a trade school within 12 months of graduating high school. In 2017, a random sample of 154 individuals who graduated from high school 12 months prior was selected. From this sample, 94 students were found to be enrolled in college or a trade school. Construct a 95% confidence interval to estimate the actual proportion of students enrolled in college or a trade school within 12 months of graduating from high school in 2017.
The confidence interval has a lower limit of enter your response here and an upper limit of enter your response here.
(Round to three decimal places as needed.)
Solution
To construct the 95% confidence interval for the proportion of students enrolled in college or a trade school within 12 months of graduating high school in 2017, follow these steps:
Step 1: Calculate the sample proportion
The sample proportion is given by:
where:
- (number of students enrolled in college or trade school),
- (total number of students in the sample).
Step 2: Determine the standard error (SE)
The standard error for the proportion is calculated using the formula:
Step 3: Find the critical value for a 95% confidence level
For a 95% confidence level, the critical value is 1.96 (from the standard normal distribution table).
Step 4: Calculate the margin of error (ME)
The margin of error is given by:
Step 5: Construct the confidence interval
The confidence interval is calculated as:
Thus, the 95% confidence interval is:
Final Answer:
- The lower limit of the confidence interval is 0.533.
- The upper limit of the confidence interval is 0.687.
Would you like further details or clarifications on the calculation steps?
Here are 5 related questions to consider:
- How would a larger sample size affect the confidence interval?
- What would happen to the confidence interval if we used a 99% confidence level?
- How is the critical value for the confidence level determined?
- How do you interpret the confidence interval in terms of real-world significance?
- How does the 2017 sample compare to the 2015 proportion of 63.8%?
Tip: A smaller confidence interval (with a narrower range) indicates more precision, but it requires a larger sample size or lower confidence level.
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Math Problem Analysis
Mathematical Concepts
Statistics
Confidence Intervals
Proportions
Formulas
Sample Proportion (p̂) = x/n
Standard Error (SE) = sqrt[p̂(1 - p̂) / n]
Margin of Error (ME) = z * SE
Confidence Interval = p̂ ± ME
Theorems
Central Limit Theorem
Suitable Grade Level
Undergraduate Statistics or Advanced High School
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