Math Problem Statement
A survey of 1010 college seniors working towards an undergraduate degree was conducted. Each student was asked, "Are you planning or not planning to pursue a graduate degree?" Of the 1010 surveyed, 658 stated that they were planning to pursue a graduate degree. Construct and interpret a 98% confidence interval for the proportion of college seniors who are planning to pursue a graduate degree. Question 28 options:
A)
(0.612, 0.690); we are 98% confident that the proportion of college seniors who are planning to pursue a graduate degree is between 0.612 and 0.690.
B)
(0.621, 0.680); we are 98% confident that the proportion of college seniors who are planning to pursue a graduate degree is between 0.621 and 0.680.
C)
(0.616, 0.686); we are 98% confident that the proportion of college seniors who are planning to pursue a graduate degree is between 0.616 and 0.686.
D)
(0.620, 0.682); we are 98% confident that the proportion of college seniors who are planning to pursue a graduate degree is between 0.620 and 0.682.
Solution
To solve this, we need to construct the 98% confidence interval for the population proportion . Here's the process:
Step 1: Calculate the sample proportion
Step 2: Determine the critical value for a 98% confidence level
For a 98% confidence level, the critical value corresponds to the 2.5% in each tail of the standard normal distribution. From the standard normal table:
Step 3: Calculate the standard error (SE)
Step 4: Compute the margin of error (ME)
Step 5: Construct the confidence interval
Final Confidence Interval:
Interpretation:
We are 98% confident that the proportion of college seniors planning to pursue a graduate degree is between 0.616 and 0.686.
Correct Answer:
C) (0.616, 0.686); we are 98% confident that the proportion of college seniors who are planning to pursue a graduate degree is between 0.616 and 0.686.
Would you like me to provide further clarifications or calculations?
Here are 5 related questions for exploration:
- How does increasing the confidence level to 99% affect the width of the interval?
- What would happen to the confidence interval if the sample size was increased to 1500 students?
- How is the critical value determined for different confidence levels?
- Why is it necessary to assume the sample is random when constructing a confidence interval?
- How does the margin of error relate to the sample size and confidence level?
Tip: The larger your sample size, the smaller the margin of
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Math Problem Analysis
Mathematical Concepts
Statistics
Confidence Intervals
Proportions
Formulas
Sample Proportion: \( \hat{p} = \frac{x}{n} \)
Standard Error: \( SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \)
Margin of Error: \( ME = z^* \cdot SE \)
Confidence Interval: \( \hat{p} \pm ME \)
Theorems
Central Limit Theorem
Suitable Grade Level
College Statistics or Advanced High School
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