Math Problem Statement
An article reported that for a sample of 48 kitchens with gas cooking appliances monitored during a one-week period, the sample mean CO2 level (ppm) was 654.16, and the sample standard deviation was 165.4.
(a) Calculate and interpret a 95% (two-sided) confidence interval for true average CO2 level in the population of all homes from which the sample was selected. (Round your answers to two decimal places.)
,
ppm
Interpret the resulting interval.
We are 95% confident that this interval contains the true population mean.We are 95% confident that this interval does not contain the true population mean. We are 95% confident that the true population mean lies above this interval.We are 95% confident that the true population mean lies below this interval.
(b) Suppose the investigators had made a rough guess of 165 for the value of s before collecting data. What sample size would be necessary to obtain an interval width of 48 ppm for a confidence level of 95%? (Round your answer up to the nearest whole number.) kitchens
Solution
(a) Calculating the 95% Confidence Interval for the True Mean CO₂ Level
To calculate a two-sided confidence interval for the population mean, we use the formula:
Where:
- (sample mean)
- (sample standard deviation)
- (sample size)
- : critical value for 95% confidence level with .
Step 1: Find
Using a -distribution table or software, the value for at 95% confidence is approximately .
Step 2: Calculate the Margin of Error (ME)
Step 3: Confidence Interval
Interpretation: We are 95% confident that the true average CO₂ level in the population of homes is between 606.13 ppm and 702.19 ppm.
(b) Determining Sample Size for Desired Interval Width
The formula for the margin of error in a confidence interval is: To achieve a desired interval width , the margin of error is half the width:
Step 1: Rearrange the Formula for
Step 2: Plug in Values
Using , , and :
Since sample size must be an integer, round up to the nearest whole number:
Answer: A sample size of 192 kitchens would be necessary to achieve a 95% confidence interval width of 48 ppm.
Recap and Questions
- (a) 95% Confidence Interval:
- (b) Required Sample Size:
- Why is the -distribution used instead of the normal distribution here?
- What factors influence the width of a confidence interval?
- How does increasing the sample size affect the confidence interval?
- What assumptions are made when calculating the confidence interval?
- How would the interval change if the sample standard deviation were smaller?
Tip: Confidence intervals provide a range of plausible values for the population mean, but they rely on the assumption of a representative sample.
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Math Problem Analysis
Mathematical Concepts
Statistics
Confidence Interval
Sample Size Determination
t-Distribution
Formulas
CI = x̄ ± t_{α/2} * (s / √n)
Margin of Error (ME) = t_{α/2} * (s / √n)
Sample Size Formula: n = (t_{α/2} * s / ME)^2
Theorems
Central Limit Theorem
Properties of the t-Distribution
Suitable Grade Level
Undergraduate Statistics
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