To find the 60th number of the Fibonacci sequence, we use the recurrence relation:

$F(n) = F(n-1) + F(n-2)$

with initial conditions:

$F(0) = 0, \quad F(1) = 1$

The Fibonacci sequence starts as follows: $0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, \dots$

You can compute the 60th Fibonacci number either by writing out all terms or using an efficient algorithm. By calculating or using a precomputed list of Fibonacci numbers, we find:

$F(60) = 1548008755920$

So, the 60th Fibonacci number is 1,548,008,755,920.

Let me know if you would like more details on the calculation or further questions!

Related questions:

1. How do you derive the Fibonacci sequence using a recursive algorithm?
2. What is the relationship between Fibonacci numbers and the golden ratio?
3. How can Fibonacci numbers be used in real-world applications?
4. What is the time complexity of calculating Fibonacci numbers using recursion versus iteration?
5. How can Fibonacci numbers be computed efficiently using matrix exponentiation?

Tip: The Fibonacci sequence grows exponentially, so even the 60th term is a large number, highlighting the rapid growth of the series!