Math Problem Statement

What is the 59th term of an arithmetic progression with initial term 45 and common difference 7

Solution

To find the 59th term of an arithmetic progression (AP), we can use the formula for the nth term of an AP:

an=a1+(n1)da_n = a_1 + (n - 1) \cdot d

Where:

  • ana_n is the nth term,
  • a1a_1 is the first term,
  • dd is the common difference,
  • nn is the term number.

Given:

  • a1=45a_1 = 45,
  • d=7d = 7,
  • n=59n = 59,

Substitute the values into the formula:

a59=45+(591)7a_{59} = 45 + (59 - 1) \cdot 7 a59=45+587a_{59} = 45 + 58 \cdot 7 a59=45+406a_{59} = 45 + 406 a59=451a_{59} = 451

Thus, the 59th term of the arithmetic progression is 451451.

Would you like more details on this, or do you have any questions?

Here are some related questions to consider:

  1. How do you find the sum of the first nn terms of an arithmetic progression?
  2. What is the formula for the sum of an arithmetic series?
  3. How do you determine if a sequence is arithmetic?
  4. What happens when the common difference of an arithmetic progression is negative?
  5. How does an arithmetic progression differ from a geometric progression?

Tip: In arithmetic sequences, the common difference (dd) remains constant, so the pattern grows or decreases linearly!

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Math Problem Analysis

Mathematical Concepts

Arithmetic Progression
Sequences
Algebra

Formulas

nth term of an AP: a_n = a_1 + (n - 1) * d

Theorems

Arithmetic Progression Formula

Suitable Grade Level

Grades 6-8