To solve this, we'll break the problem into steps:

Given Data:

• Power ($P$) = 180 kW = 180,000 W
• Line current ($I_L$) = 60 A
• Line voltage ($V_L$) = 440 V (3-phase supply)
• Frequency ($f$) = 50 Hz
• The current is leading, meaning the power factor is leading (implying a capacitive load).

Step 1: Find the apparent power ($S$) in the system.

In a 3-phase system, the apparent power ($S$) can be calculated using:

$S = \sqrt{3} \times V_L \times I_L$

Where:

• $V_L$ is the line voltage (440 V)
• $I_L$ is the line current (60 A)

$S = \sqrt{3} \times 440 \times 60$

$S = 1.732 \times 440 \times 60$

$S \approx 45,792 \text{ VA} = 45.792 \text{ kVA}$

Step 2: Find the power factor (PF).

The power factor is the ratio of real power ($P$) to apparent power ($S$):

$\text{Power Factor} = \frac{P}{S}$

$\text{Power Factor} = \frac{180,000}{45,792}$

$\text{Power Factor} \approx 0.393$

Since the current is leading, the load is capacitive with a leading power factor of 0.393.

Step 3: Determine the nature of the load components.

In a balanced 3-phase system, the real power $P$ is related to the active (resistive) load $R$ and the reactive (inductive or capacitive) load $Q$ by the following equations:

1. The active power (resistive load component) is given by:

$P = 3 \times V_{ph} \times I_{ph} \times \cos(\phi)$

Where:

• $V_{ph}$ = phase voltage = $\frac{V_L}{\sqrt{3}}$
• $I_{ph}$ = phase current = $I_L$
• $\phi$ is the phase angle corresponding to the power factor.

To find the reactive power $Q$ and the values of the load components, further steps like solving for the impedance and phase angle of the load are necessary, involving a deeper analysis.

Would you like to proceed with these detailed steps?