Math Problem Statement

What's this? Please explain it to me in detail.

What's this? Please explain it to me in detail.

Solution

The image explains the concept of rotation in the plane for coordinates in a two-dimensional space. It goes through the transformation of a point's coordinates from one coordinate system to a rotated one. Here’s a step-by-step explanation of the content:

1. Original Position of Point PP

The point PP is initially described by its position vector rP\vec{r}_P in the original (unrotated) coordinate system as: rP=(xPyP)\vec{r}_P = \begin{pmatrix} x_P \\ y_P \end{pmatrix} where xPx_P and yPy_P represent the xx- and yy-coordinates of PP in this original coordinate system.

2. Coordinates in the Rotated System

After rotating the coordinate system by an angle θ\theta, the point PP now has coordinates xPx'_P and yPy'_P in the rotated system. The new position vector rP\vec{r}'_P is: rP=(xPyP)\vec{r}'_P = \begin{pmatrix} x'_P \\ y'_P \end{pmatrix}

3. Transformation Equations

The coordinates xPx'_P and yPy'_P in the rotated system can be expressed in terms of the original coordinates xPx_P and yPy_P. Using rotation formulas, we get: xP=xPcosθ+yPsinθx'_P = x_P \cos \theta + y_P \sin \theta yP=yPcosθxPsinθy'_P = y_P \cos \theta - x_P \sin \theta These equations show how the coordinates transform under a rotation by an angle θ\theta in a counter-clockwise direction.

4. Solving for Original Coordinates xPx_P and yPy_P

To express xPx_P and yPy_P in terms of xPx'_P and yPy'_P, we rearrange the above equations: xP=xPcosθyPsinθx_P = x'_P \cos \theta - y'_P \sin \theta yP=yPcosθ+xPsinθy_P = y'_P \cos \theta + x'_P \sin \theta These are the inverse transformations, allowing you to convert back from the rotated coordinates to the original coordinates.

5. Representation with Unit Vectors

Finally, the position vector rP\vec{r}_P is expressed in terms of unit vectors ex\vec{e}_x and ey\vec{e}_y in the original system and ex\vec{e}'_x and ey\vec{e}'_y in the rotated system: rP=xPex+yPey=xP(cosθex+sinθey)+yP(cosθeysinθex)\vec{r}_P = x_P \vec{e}_x + y_P \vec{e}_y = x'_P (\cos \theta \vec{e}_x + \sin \theta \vec{e}_y) + y'_P (\cos \theta \vec{e}_y - \sin \theta \vec{e}_x) This equation shows how the position vector can be decomposed in terms of the rotated basis vectors. It reaffirms that rP\vec{r}_P can be represented in either the original or rotated coordinate system.

Summary of Key Points

  • Coordinate Transformation: The coordinates transform between systems by rotation matrices.
  • Inverse Transformation: We can recover original coordinates from rotated ones using inverse rotation.
  • Vector Representation: The point's position can be expressed in terms of rotated or original basis vectors.

Would you like further elaboration on any specific part of this transformation?


Related Questions:

  1. How do these transformations relate to rotation matrices in linear algebra?
  2. What are the applications of such coordinate transformations in physics and engineering?
  3. Could you explain how the transformation equations are derived?
  4. How does this rotation affect the length of the position vector rP\vec{r}_P?
  5. What is the significance of basis vectors ex\vec{e}_x and ey\vec{e}_y in these transformations?

Tip:

Remember that rotation transformations in a plane preserve the distance between points and the orientation (angle) relative to each other, which makes them useful in applications requiring rigid transformations, like in computer graphics and robotics.

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Math Problem Analysis

Mathematical Concepts

Coordinate Transformations
Rotation in 2D Plane
Vector Representation

Formulas

x'_P = x_P cos θ + y_P sin θ
y'_P = y_P cos θ - x_P sin θ
x_P = x'_P cos θ - y'_P sin θ
y_P = y'_P cos θ + x'_P sin θ

Theorems

Rotation Matrix
Coordinate Transformation Theorem

Suitable Grade Level

Undergraduate level (Physics, Engineering, or Mathematics students)