Math Problem Statement

Find the 23rd term of the arithmetic sequence whose common difference is d=3 and whose first term is a_1=2.

Solution

The problem asks to find the 23rd term of an arithmetic sequence where the common difference d=3d = 3 and the first term a1=2a_1 = 2.

The formula for the nn-th term of an arithmetic sequence is given by:

an=a1+(n1)da_n = a_1 + (n - 1) \cdot d

Substituting the known values:

a23=2+(231)3a_{23} = 2 + (23 - 1) \cdot 3 a23=2+223a_{23} = 2 + 22 \cdot 3 a23=2+66=68a_{23} = 2 + 66 = 68

So, the 23rd term of the arithmetic sequence is a23=68a_{23} = 68.

Would you like more details or have any questions?

Here are some related questions to deepen your understanding:

  1. What is the general formula for the sum of the first nn terms of an arithmetic sequence?
  2. How do you determine the common difference if only the first and a later term are known?
  3. Can you explain the relationship between arithmetic sequences and linear functions?
  4. How can we derive the nn-th term if only two terms of the sequence are provided?
  5. What is the geometric interpretation of an arithmetic sequence?

Tip: Always keep track of the position (n) and the common difference when working with arithmetic sequences.