Math Problem Statement

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Part 1

A youth organization collected nickels and dimes for a charity drive. By the end of the​ 1-day drive, the youth had collected

​$36.0036.00.

If there were

twotwo

times as many dimes as​ nickels, how many of each type of coin was​ collected?

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Part 1

The number of nickels was

Part 2

The number of dimes was

enter your response here.

Solution

Given the problem:

  • The total amount collected is $36.00.
  • There are twice as many dimes as nickels.
  • The number of nickels is 144.

Let's solve for the number of dimes.

Step 1: Calculate the value of the nickels

Each nickel is worth $0.05.

Value of nickels=144×0.05=7.20 dollars\text{Value of nickels} = 144 \times 0.05 = 7.20 \text{ dollars}

Step 2: Subtract the value of the nickels from the total amount collected

Remaining amount=36.007.20=28.80 dollars\text{Remaining amount} = 36.00 - 7.20 = 28.80 \text{ dollars}

Step 3: Calculate the number of dimes

Each dime is worth $0.10.

Number of dimes=28.800.10=288 dimes\text{Number of dimes} = \frac{28.80}{0.10} = 288 \text{ dimes}

Final Answer

The number of dimes collected is 288.

Would you like more details or have any questions?

Here are some related questions to consider:

  1. How would the solution change if there were three times as many dimes as nickels?
  2. What if the total collected amount was $45.00 with the same ratio of dimes to nickels?
  3. How much would the total be if only nickels were collected?
  4. How would the problem change if the number of nickels was 100 instead of 144?
  5. How would you set up an equation to find the number of nickels and dimes from the total?

Tip: When solving coin-related problems, always check the value of each coin type and the relationships between the quantities given.

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Math Problem Analysis

Mathematical Concepts

Arithmetic
Coin problems

Formulas

Value calculation formula for coins

Theorems

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Suitable Grade Level

Grades 5-7