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Part 1

A youth organization collected nickels and dimes for a charity drive. By the end of the​ 1-day drive, the youth had collected 

​$36.0036.00. 

If there were 

twotwo 

times as many dimes as​ nickels, how many of each type of coin was​ collected?

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Part 1

The number of nickels was 

144144.

Part 2

The number of dimes was 

enter your response here.




Given the problem:

- The total amount collected is $36.00.
- There are twice as many dimes as nickels.
- The number of nickels is 144.

Let's solve for the number of dimes.

### Step 1: Calculate the value of the nickels
Each nickel is worth $0.05.

\[
\text{Value of nickels} = 144 \times 0.05 = 7.20 \text{ dollars}
\]

### Step 2: Subtract the value of the nickels from the total amount collected
\[
\text{Remaining amount} = 36.00 - 7.20 = 28.80 \text{ dollars}
\]

### Step 3: Calculate the number of dimes
Each dime is worth $0.10.

\[
\text{Number of dimes} = \frac{28.80}{0.10} = 288 \text{ dimes}
\]

### Final Answer
The number of dimes collected is **288**.

Would you like more details or have any questions?

Here are some related questions to consider:

1. How would the solution change if there were three times as many dimes as nickels?
2. What if the total collected amount was $45.00 with the same ratio of dimes to nickels?
3. How much would the total be if only nickels were collected?
4. How would the problem change if the number of nickels was 100 instead of 144?
5. How would you set up an equation to find the number of nickels and dimes from the total?

**Tip:** When solving coin-related problems, always check the value of each coin type and the relationships between the quantities given.

Explore the solution to a coin collection problem involving nickels and dimes for a youth organization charity drive. Learn how to calculate the number of each type of coin based on given values and relationships. Suitable for students in Grades 5-7.

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